Answer:
1. 3
2. 2
Step-by-step explanation:
| |
x | + | 1 | | x^2 | + | 4 x | - | 2
x^3 | + | 5 x^2 | + | 2 x | + | 1
x^3 | + | x^2 | | | |
| | 4 x^2 | + | 2 x | |
| | 4 x^2 | + | 4 x | |
| | | | -2 x | + | 1
| | | | -2 x | - | 2
| | | | | | 3
__________________________________________
| |
x | - | 5 | | x^2 | - | x | + | 0
x^3 | - | 6 x^2 | + | 5 x | + | 2
x^3 | - | 5 x^2 | | | |
| | -x^2 | + | 5 x | |
| | -x^2 | + | 5 x | |
| | | | | | 2
| | | | | | 0
| | | | | | 2
Hmm,
the absolute value makes whaterver inside positive
so
find whre the abslte value is 0
1.6x-2=0
1.6x=2
x=2/1.6
x=1.25
as x approaches 1.25, the function decreases
so from left to right
from the left to right, from -ifninty to 1.25, it is decreasing
from 1.25 to infinity, it is increasing
so it is increasing in the interval (1.25,∞)
Answer:
x=2
Step-by-step explanation:
Answer:
wait hol up what
Step-by-step explanation:
but let's talk here :D