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2 years ago

C=-4 D=5 P=2 Q=-1 4cd×10×2p÷50d+20q=??

1 answer:

7 0

This is very simple; don't you worry.
Let's start by breaking down the problem so that it's not overwhelming.
For now, we're only going to focus on the very beginning of the problem -- 4c.
When a number is next to a letter with no signs in between (in terms of this kind of math), the number is called a coefficient and the letter is called a variable. When you see this in math, it means that the coefficient is being multiplied by the variable. But how do you know what the variable is?
In other examples of math, you'd have to solve for the variable, but in this case, they already give it to you! Look back at the top... what does C equal? It equals 4! This means that 4c is actually 4x4, or 4(4)!
What we just did there, changing 4c to 4 multiplied by 4, is called substitution. You just substituted the c with 4. Now you know that to solve this, you need to use the method of substitution. What do you get if you substitute all of the variables with the numbers they equal (as shown above)...?

((4*-4)*5)((10(2*2))/(50(5)))+20(-1). You didn't use parentheses to separate the term /50d + 20q, so I'm assuming that the first part of the problem is only divided by just 50d, and not 50d+20q. In the future, be sure to clarify with parentheses. Anyway...
((4*-4)*5)((10(2*2))/(50(5)))+20(-1).<span> Do NOT let this scare you. All the parentheses do is help you see what is being multiplied. All that's left is simple order of operations! You should get -<em>340 </em>as your answer.</span>

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Vertical angles are congruent <br><br> a. never<br> b. sometimes <br> c. always

yarga [219]

Answer:

Step-by-step explanation:

because vertical angles angles that are opposite each other and formed by two intersecting lines are congruent

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2 years ago

Determine the volume of the shape below?<br> 30<br> 50<br> 40

sleet_krkn [62]

Answer:

30*50*40

= 60000

Step-by-step explanation:

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3 years ago

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About 245 out of 500 students prefer walking instead of riding the bus to school. About what percent of the students prefer walk

nasty-shy [4]

Answer:

49 percent

Step-by-step explanation:

So convert the fraction into a percentage

245/500= 49%

7 0

2 years ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

1 year ago

What is the value of the expression -2^2+4x(-3) when x= -3

Kisachek [45]

It will be
(-2)^2+4*(-3)(-3) =40

6 0

3 years ago