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3 years ago

8

This is adding and subtracting of like and unlike terms ab+bc=

2 answers:

ikadub [295]3 years ago

8 0

Answer:

Step-by-step explanation:

ab+bc

b(a+b)

u can add two term only if they have same base.

NemiM [27]3 years ago

5 0

Answer:

b(a+c) this is answer okay

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Solve for k. <br><br><br> 9(3-2x)=2(10-8x)

GrogVix [38]

Answer:

Step-by-step explanation:

9(3−2x)=2(10−8x)

Step 1: Simplify both sides of the equation.

9(3−2x)=2(10−8x)

(9)(3)+(9)(−2x)=(2)(10)+(2)(−8x)(Distribute)

27+−18x=20+−16x

−18x+27=−16x+20

Step 2: Add 16x to both sides.

−18x+27+16x=−16x+20+16x

−2x+27=20

Step 3: Subtract 27 from both sides.

−2x+27−27=20−27

−2x=−7

Step 4: Divide both sides by -2.

−2x −2 = −7 /−2

x= 7/ 2

Answer:

x= 7/ 2

3 0

3 years ago

What is the greatest common factor of 7 and 10

nasty-shy [4]

The answer is 1.
7 x 1 = 7
and 10 x 1 = 10
They don't have other factors in common besides 1.

3 0

3 years ago

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A nut wholesaler sells a mix of peanuts and cashews. He charges $2.80 per pound for peanuts and $5.30 per pound for cashews. If

Len [333]

Answer: 20 pounds of peanuts and 80 pounds of cashews.

5 0

3 years ago

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Find the value of X.

Tju [1.3M]

Answer:

A number

Step-by-step explanation:

it cant be nothing

4 0

4 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago