Answer:
.........................
Answer:
Solution given:
f(x)=x²
g(x)=x+5
h(x)=4x-6
now
23:
(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25
24:
(gof)(x)=g(f(x))=g(x²)=x²+5
25:
(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36
26:
(hof)(x)=h(f(x))=h(x²)=4x²-6
27;
(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1
28:
(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14
Answer:
A:4.5
Step-by-step explanation:
all you need to do is count the spaces
Given:
The given equation is:

Where x is the number of tickets sold for the school play a y is the amount of money collected for the tickets.
To find:
The correct table of values from the given options.
Solution:
We know that the number of tickets and amount of money collected for the tickets cannot be negative. So, options A and B are incorrect.
We have,

For
,


For
,


For
,


For
,


In option C, all the ordered pairs (0,0), (10,50), (51,255), (400,2000) are in the table. So, option C is correct.
For 


Since the ordered pair (65,350) does not satisfy the given equation, therefore the option D is incorrect.
Hence, the correct option is C.