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liraira [26]
3 years ago
7

Solve 19cos θ = 5 cos θ + 14 for all values of θ if θ is measured in radians.

Mathematics
1 answer:
Bas_tet [7]3 years ago
6 0

Answer:

Ф=xπ, x={0,+∞}

Step-by-step explanation:

be 19cosФ=5cosФ+14 → 19cosФ-5cosФ-14 → 14cosФ-14=0 → cosФ=1

then,  values for which cosФ=1 are Ф=0º=360º=720º........., but the values of Ф  must be radians, so Ф=xπ, where x∈Z, not including the negative numbers,

x={0,1,2,3,....∞}

Note: π≅3.141592

when calculating the values, it must be done in radian mode

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BELP ME WITH THIS PLZ!!!!!!
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Answer:

The entire area of the sailboat is 60cm²

Step-by-step explanation:

You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.

In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.

Because the two triangles can be put together to form a single triangle, we don't need to measure them independently.  We can simply take the total length of their bases, multiply it by their height, and divide by two.  This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.

(2cm + 3cm) × 6cm

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The rectangle's area is of course equal to its width times its height, so we can say:

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3 years ago
Riley counted the number of balls on one layer of a box, 34. The box has 8 layers. How many balls can the box hold?
DedPeter [7]

Answer:

8 times 34= 272

Step-by-step explanation:

7 0
2 years ago
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elena55 [62]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Find the measure of ∠2.<br><br> and how did you find the answer??
Rufina [12.5K]
The 2 lines are parallel, so the 2 sides(e.g. 1 and 2/ 3 and 49) add up = 180 and In this case the 2 sides are equal as u can see from the original diagram so the angle  of 2 is 180-49=131.

5 0
3 years ago
having trouble with this problem, pls help :/ I know the answer, just not how to get there. (ap calc ab, integrals)
pochemuha

Answer: D) 101

Step-by-step explanation:

By linearity, we can break it up into 2 integrals. The integral and derivative of f easily cancel out

\int\limits^{10}_{-1} {(2x+0.5f'(x))} \, dx =\int\limits^{10}_{-1} {2x} \, dx +0.5\int\limits^{10}_{-1} {f'(x)} \, dx =x^2|^{^{10}}_{_{-1}}+0.5f(x)|^{^{10}}_{_{-1}}\\=(100-1)+0.5(f(10)-f(-1))=99+0.5(8-4))=101

I used the table for values of f(x) at 10 and -1. Wouldn't be surprised if this was part of a series of questions about f because I really can't see how you could use the hypothesis that f is twice differentiable on R. Same for the other table values. I'm curious about how you found the answer. Was it a different way?

7 0
2 years ago
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