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otez555 [7]
3 years ago
9

A publisher claims that the average salary paid at its company is $37,500 but it could differ as much as $4,500. Write and solve

an absolute value inequality to determine the range of salaries at this company.
|x − 37500| ≤ 4500; The salaries range from $33,000 to $42,000

|x − 37,500| ≤ 4500; The salaries are less than $33,000 or greater than $42,000.

|x − 37500| ≥ 4500; The salaries range from $33,000 to $42,000

|x − 37,500| ≥ 4500; The salaries are less than $33,000 or greater than $42,000.
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
5 0
Given:
Average salary = 37,500
differ as much as 4,500

37,500 + 4,500 = 42,000
37,500 - 4,500 = 33,000

<span>|x − 37500| ≤ 4500; The salaries range from $33,000 to $42,000</span>
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Step-by-step explanation:

For #1:

For the first one the area of the base is 8x3 which equals 24 so for base Number 1 its 24.

All we got to do to figure out the volume is multiply by 10 *the height* and then divide by 2 because we are finding the volume of a pyramid. 24x10 = 240/2 = 120. So the volume for Number 1 is 120.

For #2:

It has the exact same number except we are dealing with a rectangular prism which means at the end we don't have to divide by 2. For the base its  8 x 3 = 24 the same as the pyramid.  For the volume-  8 x 3 = 24 x 10 = 240 which means the volume is 240. And of course don't forget the unit yards³

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Answer:

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Step-by-step explanation:

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q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13

replace p in any equation and

q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92

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