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Lemur [1.5K]
3 years ago
8

Square root of 22 rounded to the nearest hundredth

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

4.69

Step-by-step explanation:

TiliK225 [7]3 years ago
3 0

Answer:

I think it's 4.69.

Step-by-step explanation:

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1. You are standing on top of a ridge using a clinometer trying to figure out how far your dog has wandered off in
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<u>Given:</u>

It is given that the ridge is 360 inches tall.

<u>Assumptions:</u>

Assume you are 170.1 cm tall which equals 67 inches tall, the height from your eye to the floor is 360+67 = 427 inches.

The distance from your eye level to the bottom of the ridge is 427 inches.

Assume the angle A is 60°.

<u>To find the distance from you to your dog.</u>

<u>Solution:</u>

A right-angled triangle can be formed where the angle is 60°, the distance between you and the dog is the hypotenuse of the triangle and your height from the floor is the adjacent side of the triangle.

Assume the hypotenuse of the triangle measures x inches.

To determine the length of the hypotenuse, we determine the cos of the angle.

cos \theta = \frac{adjacent side}{hypotenuse} .

cos A = \frac{427}{x} , x = \frac{427}{cos60} , cos60=0.5.

x=\frac{427}{0.5} = 854.

So if the ridge is 360 inches tall and you are 67 inches tall and the angle A is 60°, the distance between your dog and you is 854 inches.

3 0
3 years ago
8. The distribution for the time it takes a student to complete the fall class registration has mean of 94 minutes and standard
Alborosie

Answer:

Mean = 94

Standard deviation = 1.12

The sampling distribution of the sample mean is going to be normally distributed, beause the size of the samples are 80, which is larger than 30.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 94, \sigma = 10

By the Central Limit Theorem

The sampling distribution of the sample mean is going to be normally distributed, beause the size of the samples are 80, which is larger than 30.

Mean = 94

Standard deviation:

s = \frac{10}{\sqrt{80}} = 1.12

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3 years ago
How do I solve this?
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150/15=10
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