Answer:
Area of the regular dodecagon inscribed in a circle will be 27 square units.
Step-by-step explanation:
A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.
Since angle formed at the center by a polygon = 
Therefore, angle at the center of a dodecagon =
= 30°
Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units
Now area of a small triangle = 
where a and b are the sides of the triangle and θ is the angle between them.
Now area of the small triangle = 
= 
Area of dodecagon = 12×area of the small triangle
= 12×
= 27 unit²
Therefore, area of the regular octagon is 27 square unit.
Answer:
Step-by-step explanation:
1. a). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 10² + 24²
h = √676
h = 26
(b). Hypotenuse² = (Leg 1)² + (Leg 2)²
(25)² = (15)² + (leg 2)²
Leg 2 = √(625 - 225)
= √400
= 20
(c). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 4² + 6²
h = √(16 + 36)
h = √52
h = 2√13
(d). Hypotenuse² = (Leg 1)² + (Leg 2)²
(14)² = (Leg 1)² + 7²
Leg 1 = √(196 - 49)
= √147
= 7√3
2). Hypotenuse² = (Leg 1)² + (Leg 2)²
Leg 1 = leg 2 = 7 units [Since, triangle is an isosceles triangle]
h² = 7² + 7²
h = √98
h = 7√2
Option (1) is the correct option.
3). Hypotenuse² = (Leg 1)² + (Leg 2)²
(26)² = (Leg 1)² + (10)²
Leg 1 = √(676 - 100) = 24
Area of a right triangle = 
= 
= 120 square units
Option (3) is the correct option.
216 you multiply 12 by 18. Hope it helped!!!!!
Answer:
12x +8y +1 = 0
Step-by-step explanation:
You can write the equation by swapping the x- and y-coefficients and negating one of them. Then compute the constant that makes the line go through the given point. You can do that like this:
3(x-(-3/4)) +2(y -1) = 0
3x +9/4 +2y -2 = 0 . . . . eliminate parentheses
3x +2y +1/4 = 0 . . . . . . . simplify
To eliminate the fraction, multiply by 4:
12x +8y +1 = 0
_____
<em>Comment on the equation</em>
The line ax+by=0 passes through the origin. Replacing x and y with x-h and y-k, respectively, makes the line pass through the point (h, k). That's what we did above to make the line pass through the given point.
The business of swapping coefficients and negating one causes the slope of the new line to be the negative reciprocal of the slope of the original line. That is what makes the new line perpendicular to the original.
tan = opposite/hypotenyse
for B, this is 24/25
24/25 = 0.96