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Elden [556K]
3 years ago
12

Continuous functions f, g are known to have the properties z 4 1 f(x) dx = 19, z 4 1 g(x) dx = 12 respectively. use these to fin

d the value of the integral i = z 4 1 (8f(x) − g(x) + 7) dx. 1. i = 157 2. i = 161 3. i = 159 4. i = 163 5. i = 155
Mathematics
1 answer:
Ahat [919]3 years ago
3 0

I guess this reads

\displaystyle\int_1^4f(x)\,\mathrm dx=19

\displaystyle\int_1^4g(x)\,\mathrm dx=12

You want to compute

I=\displaystyle\int_1^4(8f(x)-g(x)+7)\,\mathrm dx

By linearity of the definite integral,

I=\displaystyle8\int_1^4f(x)\,\mathrm dx-\int_1^4g(x)\,\mathrm dx+7\int\mathrm dx

I=8\cdot19-12+7(4-1)=\boxed{161}

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. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0
3 years ago
Plz help i have to submit in 20 minutes !!!
amm1812

Answer:

Step-by-step explanation:

1. a). Hypotenuse² = (Leg 1)² + (Leg 2)²

       h² = 10² + 24²

       h = √676

       h = 26

 (b). Hypotenuse² = (Leg 1)² + (Leg 2)²

       (25)² = (15)² + (leg 2)²

       Leg 2 = √(625 - 225)

                 = √400

                 = 20

  (c). Hypotenuse² = (Leg 1)² + (Leg 2)²

        h² = 4² + 6²

        h = √(16 + 36)

        h = √52

        h = 2√13

  (d). Hypotenuse² = (Leg 1)² + (Leg 2)²

        (14)² = (Leg 1)² + 7²

         Leg 1 = √(196 - 49)

                   = √147

                   = 7√3

2). Hypotenuse² = (Leg 1)² + (Leg 2)²

    Leg 1 = leg 2 = 7 units [Since, triangle is an isosceles triangle]

    h² = 7² + 7²

    h = √98

    h = 7√2

    Option (1) is the correct option.

3). Hypotenuse² = (Leg 1)² + (Leg 2)²

    (26)² = (Leg 1)² + (10)²

    Leg 1 = √(676 - 100) = 24

    Area of a right triangle = \frac{1}{2}(\text{Leg 1})(\text{Leg 2})

                                           = \frac{1}{2}(24)(10)

                                           = 120 square units

     Option (3) is the correct option.

8 0
3 years ago
sam has 12 black and white photos and18 color photos.he wants to put the photos in equal rows so each row has either black and w
aalyn [17]
216 you multiply 12 by 18. Hope it helped!!!!!

5 0
3 years ago
Equation of a line, in general form, that is perpendicular to 2x-3y + 7 = 0 and passes through the point (-3/4, 1)
TEA [102]

Answer:

  12x +8y +1 = 0

Step-by-step explanation:

You can write the equation by swapping the x- and y-coefficients and negating one of them. Then compute the constant that makes the line go through the given point. You can do that like this:

  3(x-(-3/4)) +2(y -1) = 0

  3x +9/4 +2y -2 = 0 . . . . eliminate parentheses

  3x +2y +1/4 = 0 . . . . . . . simplify

To eliminate the fraction, multiply by 4:

  12x +8y +1 = 0

_____

<em>Comment on the equation</em>

The line ax+by=0 passes through the origin. Replacing x and y with x-h and y-k, respectively, makes the line pass through the point (h, k). That's what we did above to make the line pass through the given point.

The business of swapping coefficients and negating one causes the slope of the new line to be the negative reciprocal of the slope of the original line. That is what makes the new line perpendicular to the original.

4 0
3 years ago
Using the diagram, find tan B. Express your answer as a decimal rounded to the nearest hundredth.
Maslowich

tan = opposite/hypotenyse

for B, this is 24/25

24/25 = 0.96

7 0
3 years ago
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