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Deffense [45]
3 years ago
8

A stack of squares has 170 squares in the bottom row, 156 in the second row from the bottom, 142 in the third row from the botto

m and 128 in the fourth row from the bottom. How many squares will there be in the 11th row from the bottom ? - a table always makes these sums easier!)​
Mathematics
1 answer:
natima [27]3 years ago
4 0

9514 1404 393

Answer:

  30

Step-by-step explanation:

The sequence of square counts is ...

  170, 156, 142, 128

The differences from one row to the next are ...

  -14, -14, -14

We see that the differences are constant, so we know the sequence is an arithmetic sequence with first term 170 and common difference -14. This means the n-th term is ...

  an = a1 +d(n -1) . . . . . . for first term a1 and common difference d

  an = 170 -14(n -1)

For n=11, the number of squares is ...

  a11 = 170 -14(11 -1) = 30

There will be 30 squares in the 11th row.

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Step-by-step explanation:

so first convert it into an algebraic equation

4 - ⅛w = 16

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w=12÷ \frac{1}{8}

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2 years ago
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Tasya [4]

Answer:

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Step-by-step explanation:

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2 years ago
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hram777 [196]

Answer:

  • Option B

Step-by-step explanation:

Given is the hexagonal pyramid.

We know the radius of the base is same as its side.

<u>Find the base area:</u>

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  • A = 3√3/2*6² = 54√3

<u>Given the height and radius, find the side of the lateral triangular faces:</u>

  • \sqrt{8^2+6^2} =\sqrt{100} =10

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Step-by-step explanation:

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