Yes ma’am i’m not helping but ya know i need point so i’m just doing stuff lol
3 that’s the answer your welcome
Answer:
a) 74.0353 < u < 74.0367
b) 74.036 < u
Step-by-step explanation:
Given:
- Sample size n = 15
- Standard deviation s.d = 0.0001 in
- Sample mean x_bar = 74.036
Find:
A) Calculate the 99% two-sided confidence interval on the true mean piston diameter.
Solution:
- For 99% CI, We have a = 0.01 , and Z_a/2 = 2.58
------> (x_bar - Z_a/2*s.d / sqrt(n)) < u < (x_bar + Z_a/2*s.d / sqrt(n))
------> (74.036 - 2.58*0.0001 / sqrt(15)) < u < (74.036 + 2.58*0.0001 / sqrt(15))
------> 74.0353 < u < 74.0367
Find:
B) Calculate the 95% one-sided lower confidence interval on the true mean piston diameter.
Solution:
- For 95% lower CI, We have a = 0.05 , and Z_a = 1.645
------> (x_bar - Z_a/2*s.d / sqrt(n)) < u
------> (74.036 - 1.645*0.0001 / sqrt(15)) < u
------> 74.036 < u
Answer:
An <u>POWER</u> that has a base and an exponent.
Step-by-step explanation:
hope it's right
800 is 100% so 20 is 40% of 800.
