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Veseljchak [2.6K]
4 years ago
15

Alinn flipped a coin 20 times. The coin landed heads up 12 times and tails up 8 times.

Mathematics
1 answer:
Ainat [17]4 years ago
5 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ (12/20) = 0.6

(8/20) = 0.4

The experimental probability of the coin landing heads up is 0.6.

B) The theoretical would be considering it a fair coin.

1/2 = 0.5

The theoretical probability would be 0.5

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Hi can you help me guys please
aliina [53]

The height of the cylinder will be 5 units based on the information given.

<h3>How to calculate the height?</h3>

The cylinder has a volume of 45π cubic meters and the radius is 3 units.

The height will be calculated thus:

Volume of a cylinder = πr²h

45π = πr²h

45π = π(3²)h

45π = 9πh

h = 45π/9π

h = 5

Therefore, the height of the cylinder will be 5. units.

Learn more about volume on:

brainly.com/question/12410983

#SPJ1

7 0
2 years ago
Select the correct answer.
maksim [4K]

Answer: B

Step-by-step explanation:

5 0
3 years ago
2) Plot these points on a piece of graph paper. Draw a line to connect each of the pairs indicated. Then, determine which line i
valina [46]

2) longest line is (-1, -3) and (-1, 7)

3) (-1, -3), (-6,2), and (2,4)

5 0
3 years ago
Bit transmission errors between computers sometimes occur, where one computer sends a 0 but the other computer receives a 1 (or
lana66690 [7]

Answer:

(a) Probability that a triplet is decoded incorrectly by the receiving computer. = 0.010

(b)

(1 – p) = 0.010

(c)

E(x) = 25000 x 0.010

     = 259.2

Explanation has given below.

Step-by-step explanation:

Solution:

(a) Probability that a triplet is decoded.

2 out of three

P = 0.94, n = 3

m= no of correct bits

m   bit (3, 0.94)

At p(m≤1) = B (1; 3, 0.94)

 = 0.010

(b) Using your answer to part (a),

(1 – p) = 0.010

Error for 1 bit transmission error.

(c)  How does your answer to part (a) change if each bit is repeated five times (instead of three?

P( m ≤ 2 )

L = Bit (5, 0.94)

   = B (2; 5, 0.94)

   = 0.002

(d)  Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?

Given:

h = 25000

Bits are switched during transmission between two computers = 6% = 0.06

m = Bit (25000, 0.06)

E(m) = np

        = 25000 x 0.06

         = 1500

m = Bit (25000, 0.01)

E(m) = 25000 x 0.010

     = 259.2

3 0
3 years ago
Students counted by 8's. how many students counted to get to 112
Ymorist [56]

Answer:

14 students

Step-by-step explanation:

Its simple, you just divide 112 by 8.

6 0
3 years ago
Read 2 more answers
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