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Pavlova-9 [17]
4 years ago
12

Use synthetic division to solve(X^3+1) divide by. X-1

Mathematics
1 answer:
frozen [14]4 years ago
6 0

The answer is =x^2 +x +1 +2/x-1

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The exact circumference of a circle is 34π meters. What is the approximate area of the circle? Use 3.14 for π. Round to the near
LiRa [457]

Answer:

A = 907.46 m^{2}

Step-by-step explanation:

C = πd

34π = πd

d = 34

r = 17

A = \pi r^{2} = 3.14(17^{2}) = 3.14(289) = 907.46 m^{2}

3 0
3 years ago
A hyperbola has its foci at (1, 7) and (1, –13). A directrix of the hyperbola is y = 64/10. What is the equation of the hyperbol
lora16 [44]

Answer:

(y+3)^2/8^2 - (x-1)^2/6^2 = 1

Step-by-step explanation:

edg2020

7 0
4 years ago
Read 2 more answers
Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6). Match each set of vertices of quadrilateral EFGH with t
kykrilka [37]

Answer:

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)   a reflection across the x-axis

2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)       a translation 5 units down

3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)    a reflection across the y-axis

4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)    a translation 7 units right

Step-by-step explanation:

Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6).

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same abscissas, and the ordinates have opposite sign, then the transformation is a reflection across the x-axis.


2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same abscissas, and the ordinates of EFGH have 5 units less, then the transformation is a translation 5 units down.


3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same ordinates, and the abcissas have opposite sign, then the transformation is a reflection across the y-axis.


4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same ordinates, and the abscissas of EFGH have 7 units more, then the transformation is a translation 7 units right.

7 0
4 years ago
The composite figure is made up of a rectangle and two pentagons. Find the
NARA [144]

<u>Given:</u>

A composite figure made up of a rectangle and two pentagons.

<u>To find:</u>

The area of the composite shape.

<u>Solution:</u>

If a pentagon has a side length of s and an apothem of a, the area of the pentagon is given by

A=\frac{5}{2} (a)(s).

In the given diagram, the pentagons have side lengths of 8 units and an apothem of 5.5 units.

The area of a pentagon = \frac{5}{2} (5.5)(8) = 110 sq units.

The area of 2 such pentagons = 2(110)= 220 square units.

The rectangle has a length of 14 units and a width of 8 units.

The area of a rectangle = (l)(w).

The area of the rectangle = (14)(8)=112 square units.

The area of the composite shape is the sum of the individual areas of the different shapes.

The area of the composite shape =220+112=332 sq units.

The area of the composite shape is option A. 332 sq units.

4 0
3 years ago
Choose Yes or No to tell if the fraction 4/9
77julia77 [94]
Yes
Yes
Maybe? The answer is 42.6
Yes
5 0
3 years ago
Read 2 more answers
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