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IRISSAK [1]
3 years ago
8

Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6). Match each set of vertices of quadrilateral EFGH with t

he transformation that shows it is congruent to ABCD. E(-3, -4), F(1, -3), G(3, -6), and H(1, -6) a translation 7 units right E(-3, -1), F(1, -2), G(3, 1), and H(1, 1) a reflection across the y-axis E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6) a reflection across the x-axis E(4, 4), F(8, 3), G(10, 6), and H(8, 6) a translation 5 units down
Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)   a reflection across the x-axis

2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)       a translation 5 units down

3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)    a reflection across the y-axis

4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)    a translation 7 units right

Step-by-step explanation:

Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6).

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same abscissas, and the ordinates have opposite sign, then the transformation is a reflection across the x-axis.


2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same abscissas, and the ordinates of EFGH have 5 units less, then the transformation is a translation 5 units down.


3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same ordinates, and the abcissas have opposite sign, then the transformation is a reflection across the y-axis.


4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same ordinates, and the abscissas of EFGH have 7 units more, then the transformation is a translation 7 units right.

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Answer:

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mrs_skeptik [129]
<h3>Given</h3>
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The circumference and radius of a circle are related by

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so the radius in terms of circumference is

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