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IRISSAK [1]
3 years ago
8

Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6). Match each set of vertices of quadrilateral EFGH with t

he transformation that shows it is congruent to ABCD. E(-3, -4), F(1, -3), G(3, -6), and H(1, -6) a translation 7 units right E(-3, -1), F(1, -2), G(3, 1), and H(1, 1) a reflection across the y-axis E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6) a reflection across the x-axis E(4, 4), F(8, 3), G(10, 6), and H(8, 6) a translation 5 units down
Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)   a reflection across the x-axis

2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)       a translation 5 units down

3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)    a reflection across the y-axis

4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)    a translation 7 units right

Step-by-step explanation:

Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6).

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same abscissas, and the ordinates have opposite sign, then the transformation is a reflection across the x-axis.


2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same abscissas, and the ordinates of EFGH have 5 units less, then the transformation is a translation 5 units down.


3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same ordinates, and the abcissas have opposite sign, then the transformation is a reflection across the y-axis.


4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case the vertices has the same ordinates, and the abscissas of EFGH have 7 units more, then the transformation is a translation 7 units right.

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1. A snack bar sells two sizes of snack packs. A large snack pack is $8, and a
natali 33 [55]

answer

system : 8L+ 4S = 120

               L + S = 20

There are 10 small packs and 10 large packs

step by step answer :

to form the two systems, we have to determine the catagories of the 2 equations : one for money and one for the no of packs

after forming the two equations we simply put the numbers in the same order put above on the calculator ( mode 5:1) and the calaculator will answer it in seconds . 10 small packs and 10 large packs.

To  check your answer , substitute the letters with their values and if both equations gave you the same value at the end then your answer is correct!  

7 0
3 years ago
The bigger
Arte-miy333 [17]

Answer:

See Explanation

Step-by-step explanation:

Required

Prove that Dexter is wrong

To prove that Dexter is wrong, we use the following numbers.

Number = 4

The factors are:

Factor = 1,2\ and\ 4

3 factors

Using a greater number:

Number = 5

The factors are:

Factor = 1\ and\ 5

2 factors

From the above analysis:

4 has 3 factors and 5 has 2 factors; which shows that 5 has fewer factors

This shows that Dexter is wrong

5 0
2 years ago
How do you find the area of the shaded region
Amiraneli [1.4K]

well, first off, let's notice that we have a trapezoid with a rectangle inside it, so the rectangle is really "using up" area that the trapezoid already has.

now, if we just get the area of the trapezoid, and then the area of the rectangle alone, and then subtract that area of the rectangle, the rectangle will in effect be making a hole inside the trapezoid's area, and what's leftover, is the shaded section, that part the hole is not touching.

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h&=height\\ a,b&=\stackrel{parallel~sides}{bases} \\\cline{1-2} h&=8\\ a&=16\\ b&=8 \end{cases}\implies A=\cfrac{8(16+8)}{2}\implies A=96 \\\\\\ \stackrel{\textit{area of the rectangle}}{(5\cdot 3)\implies 15}~\hfill \stackrel{~\hfill \textit{shaded area}}{\stackrel{\textit{trapezoid}}{96}~~ - ~~\stackrel{\textit{rectangle}}{15}~~ = ~~81}

3 0
3 years ago
3 semicircles are connected to 3 sides of a square. each side of the square measures 4 centimeters. what is the area of the comp
puteri [66]

The area of the composite figure  with 3 semicircles connected to 3 sides of a square is (6π+16)cm^{2}.

<h3 /><h3>What is a semicircle?</h3>

A semicircle is a plane shape that is a part of a circle divided into two equal parts through its diameter.

Analysis:

Since the semicircles are connected to 3 sides of a square 4cm, the diameter of the semicircle is 4cm.

Radius of semicircle = 4/2 = 2cm

Area of a semicircle = πr^{2}/2 = \pi(2)^{2}/2 = 2πcm^{2}

For three semicircles = 3 x 2πcm^{2} = 6πcm^{2}

Area of square = s^{2} = (4)^{2} = 16cm^{2}

Area of composite figure  = Area of 3 semicircles + area of square

Area of composite figure = (16 + 6π)cm^{2}

In conclusion, the area of the composite figure is  (16 + 6π)cm^{2}.

Learn more about  area of plane shapes: brainly.com/question/20475473

#SPJ4

5 0
1 year ago
#9 how do we do it and what is the answer
andreev551 [17]
Make a graph then point all of the number
3 0
3 years ago
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