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natita [175]
3 years ago
10

Write 4.81 as a mixed number in simplest form.

Mathematics
2 answers:
Gelneren [198K]3 years ago
5 0

Answer:

Step-by-step explanation:

4.81

=\frac{ 481}{100} \\=4\frac{81}{100}

Lady_Fox [76]3 years ago
4 0

Answer:

4 \frac{81}{100}

Step-by-step explanation:

A mixed number is a combination of a whole number with a fraction. To make the fraction part, we need to take the decimal. In this case, the decimal is .81

.81 is equivalent to 81/100

81/100 is already in its simplest from since 81 is not divisible by 2

The final answer is 4 \frac{81}{100}

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When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w
deff fn [24]

Answer:

A 90% confidence interval for <em>p</em> will be <u>narrower </u>than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - <em>α</em>) % confidence interval for a population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Here \hat p is the sample proportion.

The margin of error of the confidence interval is:

MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The MOE is dependent on:

  1. Confidence level
  2. Standard deviation
  3. Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645

And the critical value of <em>z</em> for 99% confidence level is:

z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for <em>p</em> will be narrower than the 99% confidence interval.

6 0
3 years ago
What are the roots of x2 + 8x – 48 = 0? <br> show me the work
nekit [7.7K]
<span>x^2 + 8x – 48 = 0
That is a quadratic equation where
a = 1
b = 8
c = -48
We can solve it by using the quadratic formula:
x = [-b +-sq root (b^2 - 4ac)] / 2a
x = [-8 +- sq root (64 -4*1*-48)] / 2*1
</span><span>x = [-8 +- sq root (256)] / 2
x = [-8 +-16] / 2
x1 = 8 / 2 = 4
x2 = -24 / 2 = -12





</span>
8 0
3 years ago
Find the values of a and b such that x² + 2x - 7 = ( x + a )² + b
gizmo_the_mogwai [7]

Answer:

<em>a = 1 ; b = - 8 </em>

Step-by-step explanation:

x² + 2x - 7 = (x² + 2x + 1) - 1 - 7 =<u><em> (x + 1)² - 8 </em></u>

<em>a = 1 </em>

<em>b = - 8</em>

8 0
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The answer is -2x + 3
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