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Citrus2011 [14]
3 years ago
13

Rewrite the product as a power:

Mathematics
1 answer:
dem82 [27]3 years ago
7 0

Answer:

b+3x^3

x+2y+2z+2

32a^5

Step-by-step explanation:

none needed [=

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What are the x-coordinates of the solutions to this system of equations? x2 + y2 = 100 y = x + 2
kiruha [24]

Answer:

x = - 8, x = 6

Step-by-step explanation:

Given the 2 equations

x² + y² = 100 → (1)

y = x + 2 → (2)

Substitute y = x + 2 into (1)

x² + (x + 2)² = 100

x² + x² + 4x + 4 = 100

2x² + 4x + 4 = 100 ( subtract 100 from both sides )

2x² + 4x - 96 = 0 ( divide through by 2 )

x² + 2x - 48 = 0 ← in standard form

(x + 8)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 6 = 0 ⇒ x = 6

6 0
3 years ago
The same number of people live on the islands Beautiful Sunrise and Gorgeous
aev [14]

Using the percentage concept, it is found that 75% of the population of Gorgeous Sunset is on Beautiful Sunrise now.

<h3>What is a percentage?</h3>

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

P = \frac{a}{b} \times 100\%

In this problem, we have that:

  • We consider that the population of both Beautiful Sunrise and Gorgeous Sunset islands is of x.
  • There is a fiesta at Beautiful Sunrise, and a number a of people from Gorgeous Sunset are coming, hence, there will be x + a people at Beautiful Sunrise and x - a people t Gorgeous Sunset.

The percentage of people from Gorgeous Sunset is on Beautiful Sunrise now is:

P = \frac{a}{x} \times 100\%

Now the number of people on Beautiful Sunrise is seven times the number of people on Gorgeous Sunset, hence:

\frac{x + a}{x - a} = 7

We can find a <u>as a function of x</u> to find the percentage:

\frac{x + a}{x - a} = 7

7(x - a) = x + a

7x - 7a = x + a

8a = 6x

a = \frac{3x}{4}

Then, the percentage is:

P = \frac{a}{x} \times 100\%

P = \frac{\frac{3x}{4}}{x} \times 100\%

P = \frac{3}{4} \times 100\%

P = 75\%

75% of the population of Gorgeous Sunset is on Beautiful Sunrise now.

You can learn more about the percentage concept at brainly.com/question/10491646

7 0
2 years ago
Mutiply 4y-4w^8-3y^5w^3
sukhopar [10]

Answer:

48y⁶w¹¹

Step-by-step explanation:

[-3y⁵][4y] → -12y⁶

×

[w³][-4w⁸] → -4w¹¹

______

48y⁶w¹¹

I am joyous to assist you anytime.

8 0
4 years ago
Consider the transpose of Your matrix A, that is, the matrix whose first column is the first row of A, the second column is the
Zarrin [17]

Answer:The system could have no solution or n number of solution where n is the number of unknown in the n linear equations.

Step-by-step explanation:

To determine if solution exist or not, you test the equation for consistency.

A system is said to be consistent if the rank of a matrix (say B ) is equal to the rank of the matrix formed by adding the constant terms(in this case the zeros) as a third column to the matrix B.

Consider the following scenarios:

(1) For example:Given the matrix A=\left[\begin{array}{ccc}1&2\\3&4\end{array}\right], to transpose A, exchange rows with columns i.e take first column as first row and second column as second row as follows:

Let A transpose be B.

∵B=\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]

the system Bx=0 can be represented in matrix form as:

\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right] ................................eq(1)

Now, to determine the rank of B, we work the determinant of the maximum sub-square matrix of B. In this case, B is a 2 x 2 matrix, therefore, the maximum sub-square matrix of B is itself B. Hence,

|B|=(1*4)-(3*2)= 4-6 = -2 i.e, B is a non-singular matrix with rank of order (-2).

Again, adding the constant terms of equation 1(in this case zeros) as a third column to B, we have B_{0}:      

B_{0}=\left[\begin{array}{ccc}1&3&0\\4&2&0\end{array}\right]. The rank of B_{0} can be found by using the second column and third column pair as follows:

|B_{0}|=(3*0)-(0*2)=0 i.e, B_{0} is a singular matrix with rank of order 1.

Note: a matrix is singular if its determinant is = 0 and non-singular if it is \neq0.

Comparing the rank of both B and B_{0}, it is obvious that

Rank of B\neqRank of B_{0} since (-2)<1.

Therefore, we can conclude that equation(1) is <em>inconsistent and thus has no solution.     </em>

(2) If B=\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right] is the transpose of matrix A=\left[\begin{array}{ccc}-4&-8\\5&10\end{array}\right], then

Then the equation Bx=0 is represented as:

\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right]..................................eq(2)

|B|= (-4*10)-(5*(-8))= -40+40 = 0  i.e B has a rank of order 1.

B_{0}=\left[\begin{array}{ccc}-4&5&0\\-8&10&0\end{array}\right],

|B_{0}|=(5*0)-(0*10)=0-0=0   i.e B_{0} has a rank of order 1.

we can therefor conclude that since

rank B=rank B_{0}=1,  equation(2) is <em>consistent</em> and has 2 solutions for the 2 unknown (X_{1} and X_{2}).

<u>Summary:</u>

  • Given an equation Bx=0, transform the set of linear equations into matrix form as shown in equations(1 and 2).
  • Determine the rank of both the coefficients matrix B and B_{0} which is formed by adding a column with the constant elements of the equation to the coefficient matrix.
  • If the rank of both matrix is same, then the equation is consistent and there exists n number of solutions(n is based on the number of unknown) but if they are not equal, then the equation is not consistent and there is no number of solution.
5 0
3 years ago
Can someone please help<br><br> I’m in primary school
muminat
I synonym for road is street
A synonym for travel is move
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8 0
3 years ago
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