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3 years ago

Simplify the expresiontan-x

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

6 0

Answer:

I wouldn't even say that the answer is 0.

Step-by-step explanation:

I say that because you can not simplify -x.

You might be interested in

How do you factor x^2+11x+10=0?

xz_007 [3.2K]

Answer:

x = -1 or x = -10

Step-by-step explanation:

x^2 + 11x + 10 = 0

x^2 + 10x + x + 10 = 0

x(x + 10) + 1(x + 10) = 0

(x + 1) (x + 10) = 0

x + 1 = 0 or x + 10 = 0

x = -1 or x = -10

8 0

4 years ago

9,13,43,55 what is the mean absolute deviate (MAD) of their ages

lisov135 [29]

Answer:

The mean absolute deviation of this data $\{9,13,43,55\}$ is $MAD =19$ .

Step-by-step explanation:

The mean absolute deviation (MAD) of a dataset is the average distance between each data point and the mean. It gives us an idea about the variability in a dataset.

The steps to find the MAD include:

find the mean (average)
find the difference between each data value and the mean
take the absolute value of each difference
find the mean (average) of these differences

To find the mean absolute deviation of this data $\{9,13,43,55\}$ you must

Step 1: Calculate the mean.

$\:mean=\bar{x}= \frac{9+13+43+55}{4} =\frac{120}{4}=30$

Step 2: Calculate the distance between each data point and the mean and take the absolute value of each difference .

$|9-30|=21\\|13-30|=17\\|43-30|=13\\|55-30|=25$

Step 3: Add the distances together.

$21+17+13+25=76$

Step 4: Divide the sum by the number of data points.

$MAD = \frac{76}{4} =19$

7 0

4 years ago

What is the center of the circle X2 + y2 = 28+ 3x?

notka56 [123]

Answer:

The center is $(\frac{3}{2},0)$ .

The problem:

What is the center of the circle X2 + y2 = 28+ 3x?

Step-by-step explanation:

We need to put anything with an $x$ together and anything with a $y$ together:

$x^2+y^2=28+3x$

Subtract $3x$ on both sides:

$(x^2+y^2)-3x=(28+3x)-3x$

$x^2-3x+y^2=28$

We need to complete the square for $x$ 's. The $y$ 's are already done.

Keep in mind: $x^2+bx+(\frac{b}{2})^2=(x+\frac{b}{2})^2So we are going to add [tex](\frac{-3}{2})^2$ on both sides so we can use this identity for the left side with the $x$ 's: