All categories

3 years ago

Find the missing segments in this 30-60-90 right triangle AB=8 BC=4 CD=?

Mathematics

2 answers:

Georgia [21]3 years ago

4 0

CD= 12 I think if its wrong I'm so sorry

Oxana [17]3 years ago

4 0

I'm guessing that CD would be the 'altitude' of the of the right triangle, also considered as a leg, too, with also AB being the hypotenuse. If this is the case, then CD would measure 4√3. Hope this helps.

You might be interested in

Archy [21]

Answer: 5h+9

Step-by-step explanation:

10h + (-5h)

5h+(6(+3))

6 0

2 years ago

you and two friends pay $40 for tickets. the cost was divided three ways in the ratio 1:3:6. how much did each person pay9

Musya8 [376]

1+3+6=10
40=10 units
diidde by 10
4=1unit

4 times 1=4
4 times 3=12
4 times 6=24

they paid $4, $12 and $24

5 0

3 years ago

Pre-Algebra <br> Due now<br> Please help, thank you

slamgirl [31]

Answer:

1. The $\sqrt{10}$ is between 3 and 4.

2. The $\sqrt{54}$ is between 7 and 8.

3. The $\sqrt{18}$ is between 4 and 5.

4. The $\sqrt{99}$ is between 9 and 10.

5. The $\sqrt{41}$ is between 6 and 7.

Step-by-step explanation:

1. $\sqrt{10}$ : 10 is near the perfect squares 9 and 16, which would mean its answer is between their square roots which are 3 and 4.

2. $\sqrt{54}$ : 10 is near the perfect squares 49 and 64, which would mean its answer is between their square roots which are 7 and 8.

3. $\sqrt{18}$ : 10 is near the perfect squares 16 and 25, which would mean its answer is between their square roots which are 4 and 5.

4. $\sqrt{99}$ : 10 is near the perfect squares 81 and 100, which would mean its answer is between their square roots which are 9 and 10.

5. $\sqrt{41}$ : 10 is near the perfect squares 36 and 49, which would mean its answer is between their square roots which are 6 and 7.

8 0

2 years ago

Read 2 more answers

the times of all 15 year olds who run a certain race are approximately normally distributed with a given mean

Butoxors [25]

The percentage of the runners who have times less than 14.4 sec is 0.15%

The times of all 15-year old who run a certain race are approximately normally distributed with a given mean of 18 sec and a standard deviation of 1.2 sec.

We know that,

where,

X = raw score = 14.4

μ = mean = 18

σ = standard deviation = 1.2

Putting the values,

Finding the probability from the z score table, we get

P(z < -3) = 0.00135 = 0.135%

Disclaimer: The question is incomplete. Please read below to find the missing content.

Question: The times of all 15-year-olds who run a certain race are approximately normally distributed with a given mean of 026-1 = 18 seconds and a standard deviation of 026-2. = 1.2 sec. What percentage of the runners have times less than 14.4 seconds?

0.15%

0.30%

0.60%

2.50%

Learn more about percentages here brainly.com/question/809966

#SPJ4

8 0

2 years ago

6x - 2y = 13<br> 2х + Зу = -3

miv72 [106K]

Answer:

6x-2y=13 is x= $\frac{2y+13}{6}$ solved for x