120 * .08= 9.6
120 - 9.6= 110.4
Let us set up some variables:
Now let us set up some equations based on the facts:
- length of rectangle is 4 times its width --> L = 4W
- perimeter of rectangle is 80 --> 2L + 2W = 80
Equations:
L = 4W -- equation 1
2L + 2W = 80 -- equation 2
Plug the value of L from equation 1 into equation 2
2(4W) + 2W = 80
8W + 2W = 80
10W = 80
W = 8 -- equation 3
Plug the value of W from equation 3 into equation 1:
L = 4W = 4 * 8 = 32
Therefore the length is 32 and the width is 8.
Hope that helps!
Answer:
Step-by-step explanation:
Given: quadrilateral ABCD inscribed in a circle
To Prove:
1. ∠A and ∠C are supplementary.
2. ∠B and ∠D are supplementary.
Construction : Join AC and BD.
Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,
∠1=∠2-----(1)
∠3=∠4-----(2)
∠5=∠6-------(3)
∠7=∠8------(4)
Also, sum of angles of quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°
→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4
→→→2∠1+2∠4+2∠6+2∠8=360°
→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,
→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)
As, ∠A+∠B+∠C+∠D=360°
∠A+∠C+180°=360°
∠A+∠C=360°-180°------Using A
∠A+∠C=180°
Hence proved.
credit: someone else
Answer:
The 29th term is
<h2>243</h2>
Step-by-step explanation:
The above sequence is an arithmetic sequence
For an nth term in an arithmetic sequence
U(n) = a + ( n - 1)d
where n is the number of terms
a is the first term
d is the common difference
From the question
a = - 121
d = -108 -- 121 = - 108 + 121 = 13
Since we are finding the 29th term
n = 29
The 29th term of the sequence is
U(29) = - 121 + ( 29 - 1) 13
= -121 + 28(13)
= -121 + 364
The final answer is
<h2>243</h2>
Hope this helps you
Answer:
Step-by-step explanation:
we have
-----> equation A
-----> equation B
To find out (V of r)(t) substitute equation B in equation A
