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____ [38]
3 years ago
7

Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. In one day, 282 passes were sold

for a total of $10,680. How many unlimited-ride passes were sold?
Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

Number of Unlimited passes sold were 168.

Step-by-step explanation:

Let Number of Unlimited passes sold be x

and Number of entrance-only passes sold be y.

Total number of passes sold =282

Hence,

x+y=282 \ \ \ \ equation \ 1

Also

Cost for unlimited-ride pass = $50

Cost for entrance-only pass = $20

Total Money for one day = $10,680

Hence,

\$50x+\$20y=\$10,680\\

Dividing by 10 on both side we get;

5x+2y=1068 \ \ \ \ equation \ 2

Now multiplying equation 1 by 2 we get;

2x+2y=584 \ \ \ \ equation \ 3

Now Subtracting equation 3 from equation 2 we get;

(5x+2y=1068)-(2x+2y=584)\\3x=504\\x=\frac{504}{3}= 168

x= 168

x+y = 282

168+y =282

y=282-168

y= 114

Hence, Number of Unlimited passes sold are 168 and Number of entrance-only pass sold is 114.

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