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____ [38]
3 years ago
7

Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. In one day, 282 passes were sold

for a total of $10,680. How many unlimited-ride passes were sold?
Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

Number of Unlimited passes sold were 168.

Step-by-step explanation:

Let Number of Unlimited passes sold be x

and Number of entrance-only passes sold be y.

Total number of passes sold =282

Hence,

x+y=282 \ \ \ \ equation \ 1

Also

Cost for unlimited-ride pass = $50

Cost for entrance-only pass = $20

Total Money for one day = $10,680

Hence,

\$50x+\$20y=\$10,680\\

Dividing by 10 on both side we get;

5x+2y=1068 \ \ \ \ equation \ 2

Now multiplying equation 1 by 2 we get;

2x+2y=584 \ \ \ \ equation \ 3

Now Subtracting equation 3 from equation 2 we get;

(5x+2y=1068)-(2x+2y=584)\\3x=504\\x=\frac{504}{3}= 168

x= 168

x+y = 282

168+y =282

y=282-168

y= 114

Hence, Number of Unlimited passes sold are 168 and Number of entrance-only pass sold is 114.

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The ratio of forks to spoons in the cafeteria is 15:25. If the total
9966 [12]

Answer:

30 forks

Step-by-step explanation:

Let's start by simplifying the given ratio. Since both 15 and 25 are multiples of 5, we can divide the whole ratio by 5.

Forks: spoons

= 15: 25

= 3: 5

This means that forks take up 3 units of the total number of utensils, while the number of spoons is 5 units of the total number of utensils.

Number of forks= 3u

Number of spoons= 5u

Units shall be represented by the letter u from this point forth.

Now, we can form an equation using the total number of utensils in the cafeteria.

Assuming that the utensils in the cafeteria are only forks and spoons,

number of fork and spoons= 80

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8u= 80

Let's solve for u.

Divide by 8 on both sides:

1u= 80 ÷8

1u= 10

This means that 1 unit represents 10 utensils.

Substitute the value of u into the expression of the number of forks:

Number of forks

= 3u

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8 0
2 years ago
Shona spins a spinner with three equal-sized spaces—red, green, and yellow—and then rolls a six-sided die numbered from 1 to 6.
telo118 [61]
<h2>Answer with explanation:</h2>

<u>Sample size--</u>

It is the collections of all the possible outcomes of an event.

(A)

It is given that:

Shona spins a spinner with three equal-sized spaces—red, green, and yellow and then rolls a six-sided die numbered from 1 to 6.

This means that the possible outcomes are given as follows:

(Red,1)          (Green,1)           (Yellow,1)

(Red,2)         (Green,2)          (Yellow,2)

(Red,3)         (Green,3)           (Yellow,3)

(Red,4)         (Green,4)           (Yellow,4)

(Red,5)         (Green,5)           (Yellow,5)

(Red,6)         (Green,6)           (Yellow,6)

This means that the total number of outcomes are: 18

Hence, the sample size for this compound event is:  18

(B)

If the spinner has four colored spaces.

Let the fourth color be: Blue

Then the possible outcomes are given by:

(Red,1)          (Green,1)           (Yellow,1)           (Blue,1)

(Red,2)         (Green,2)          (Yellow,2)          (Blue,2)

(Red,3)         (Green,3)           (Yellow,3)          (Blue,3)

(Red,4)         (Green,4)           (Yellow,4)          (Blue,4)  

(Red,5)         (Green,5)           (Yellow,5)          (Blue,5)

(Red,6)         (Green,6)           (Yellow,6)          (Blue,6)

Hence, the total number of outcomes are:  24

The sample size of this compound event would be 24.

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