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Alex_Xolod [135]
3 years ago
15

What is the product? 6(x^2-1) times 6x-1 over 6(x+1)

Mathematics
2 answers:
sergejj [24]3 years ago
8 0

(36x^3-36x-1)/6x+6 or 6x^2-6x+(-1/6x+6)

gregori [183]3 years ago
8 0

For this case we must find the product of the following expression:

6 (x ^ 2-1) * \frac {6 (x-1)} {6 (x + 1)}

We can rewrite x ^ 2-1 as:

(x + 1) (x-1), then:

6 (x + 1) (x-1) * \frac {6 (x-1)} {6 (x + 1)} =

Canceling similar terms of the numerator and denominator:

(x-1) * 6 (x-1) =\\6 (x-1) ^ 2

ANswer:

6 (x-1) ^ 2

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3x-50 (7x) find the value of x
Naya [18.7K]

x=23

Simplifying

(3x + -50) + (7x)

Reorder the terms:

(-50 + 3x) + (7x)

Remove parenthesis around (-50 + 3x)

-50 + 3x + (7x) =

Combine like terms: 3x + (7x)

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Solving

-50 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.

-50 + 50 + 10x = 180 + 50

Combine like terms: -50 + 50 = 0

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Simplifying

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m = 77
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