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coldgirl [10]
2 years ago
10

Been stuck on this for a while man...

Mathematics
1 answer:
sesenic [268]2 years ago
7 0

Answer:

2)y=6

4)36=a

Step-by-step explanation:

8y=48

/8    /8

y=6

18=a/2

*2    *2

36=a

You wanna get x by itself

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Mya told her friend, “If you increase my sisters age by 6, multiply that quantity by 12, and then subtract 4, you get 10. Write
Lostsunrise [7]

Answer: x+6(12-4) = 10

Step-by-step explanation:

7 0
3 years ago
Given the relation in the table, what is the product of h(3) and h(5)?​
denis23 [38]

Answer:

<h3>3</h3>

Step-by-step explanation:

h(3) = 1

h(5) = 3

Their products :

3 \times 1 \\  = 3

6 0
3 years ago
Rabekah is filling a cube-shaped box with small cubes. the volume of each of these cubes is 1 cubic centimeter. She has already
Vinvika [58]
Well it shows that the main cube is 9 blocks tall. It is a perfect cube, not a rectangular prism or anything, so every side is the same. So 9 cubed. Or, in other words, 9*9*9
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3 years ago
How do you solve: secx=-5/2, tanx&lt;0<br><br> Find all six trig functions
Brut [27]

Answer:

sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21

Step-by-step explanation:

During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.

5 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}

6 0
3 years ago
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