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Mkey [24]
3 years ago
11

Solve the inequality 1/2x<10

Mathematics
2 answers:
DedPeter [7]3 years ago
8 0

Answer:

x < 20

Step-by-step explanation:

1/2x < 10

Multiply both sides by 2:-

x < 20

mamaluj [8]3 years ago
4 0
1\2×20=10
1\2×19<10
x<20
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sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

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The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

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3 years ago
Blank divided by blank equals 6 what is the two blanks
Travka [436]
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4 0
3 years ago
Read 2 more answers
Thanks for the help!
Bogdan [553]

Hope you could understand.

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Why do you need axioms in theorems? <br>​
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<h3>Hope it helps...</h3>
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