Observe the given data distribution table carefully.
The 5th class interval is given as,
The upper limit (UL) and lower limit (LL) of this interval are,
Thus, the upper-class limit of this 5th class is 17.4.
Find the length of the diameter of circle O. Round to the nearest tenth.
1 answer:
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(please open my photo for reference as you read, I am a visual learner/explainer so it will make the most sense that way)
So the first thing you want to do is look at the exterior angle 130°. A straight line is 180°, and every Triangle's angular sum is 180°. How I think of it is that every straight line has a mini protractor on either side. It makes it a bit easier to understand.
180 - 130 = 50
You now know that two of the angles are 50°.
You now have two of the measurements for the triangle farthest to the left.
75° and 50°
75 + 50 = 125
180 - 125 = 55
a = 55°
Now that you have all the measurements for the first triangle, let's move onto the next one.
With two measurements for the second triangle, all you need to do is find their sum and subtract that from 180 and you will have the third measurement!
50 + 60 = 110
180 - 110 = 70
b = 70°
Finally, for the last triangle, you already have two of the measurements 60° and 85°.
85 + 60 = 145
180 - 145 = 35
c = 35°
Sorry if this explanation is a bit messy, it's hard to describe certain things without a letter or some kind of name to differentiate between them verbally.
I hope this helps! <3
