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Irina18 [472]
4 years ago
12

Use long division to find the quotient​ Q(x) and the remainder​ R(x) when​ P(x) is divided by​ d(x) and express​ P(x) in the for

m ​d(x) times •​Q(x)plus+​R(x).
​P(x=x^3 + 2x^2 - 11 x + 471
​ d(x)=x+9

​P(x)=​(x+9) (blank) + blank

Mathematics
1 answer:
lilavasa [31]4 years ago
4 0

Answer:

P(x)=(x+9)(x^2-7x+52)+3

Step-by-step explanation:

We are given that

P(x)=x^3+2x^2-11x+471

d(x)=x+9

We have to find the value of Q(x) and Remainder R(x).

Quotient, Q(x)=x^2-7x+52

Remainder,R(x)=3

We know that

Dividend=Divisor\times Quotient+Remainder

P(x)=(x+9)(x^2-7x+52)+3

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<span>The speed is 57.5 m/s and the parachutist will fall 1150 m in 20 seconds.

Explanation<span>:
We start out with the ratio 207 km/1 hr.

We know that 1 km = 1000 m; this means 207 km = 207*1000 = 207000 m. This gives us 207000 m/1 hr.

We know that 1 hr = 60 minutes, so we have 207000 m/60 min.

We also know that 1 min = 60 seconds, so 60 min = 60*60 = 3600 sec; this gives us 207000 m/3600 sec.

Dividing this, we get 57.5 m/s.

In 20 seconds, the parachutist will fall 57.5(20) = 1150 m.</span></span>
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Step-by-step explanation:

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A solution with a pH of 11 has a [H+] of:<br> 11<br> 1 x 10-3<br> 1 x 10-11<br> 1 x 1011<br> 1 x 103
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A solution with a pH of 11 has a [H+] of 1.0\times 10^{-11}

Option B is correct option.

Step-by-step explanation:

A solution with a pH of 11 has a [H+] of= ?

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Concentration of H+ [H+]= ?

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Putting values and finding [H+]

pH=-log[H+]\\\,[H+]\,=10^{-pH}\\\,[H+]\,=10^{-11}\\\,[H+]\,=1.0\times 10^{-11}

So, A solution with a pH of 11 has a [H+] of 1.0\times 10^{-11}

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Let x be the weight of the package.

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