Answer:
4 consecutive goals
Step-by-step explanation:
If 3 of last 10 field goals = 30%
Which is equivalent to
(Number of goals scored / total games played) * 100%
(3 / 10) * 100% = 30%
Number of consecutive goals one has to score to raise field goal to 50% will be:
Let y = number of consecutive goals
[(3+y) / (10+y)] * 100% = 50%
[(3+y) / (10+y)] * 100/100 = 50/100
[(3+y) / (10+y)] * 1 = 0.5
(3+y) / (10+y) = 0.5
3+y = 0.5(10 + y)
3+y = 5 + 0.5y
y - 0.5y = 5 - 3
0.5y = 2
y = 2 / 0.5
y = 4
Therefore, number of consecutive goals needed to raise field goal to 50% = 4
Answer:
7
Step-by-step explanation:
Its 7 because khan academy and i know it
Answer:
Step-by-step explanation:
<h3>Method 1:</h3>
<h3>Method 2:</h3>
Answer:
Move all terms that don't contain x to the right side and solve.
x
= 5
/3 − 4
y
/3
V/LW=H , you have to isolate the h so you must divide both sides by LW
