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Scrat [10]
3 years ago
13

The sum of two numbers is 92. One eighth of the larger number plus one third of the smaller number is 19. Find the numbers.​

Mathematics
1 answer:
maria [59]3 years ago
8 0

Answer:

The numbers 'x' and 'y' are:

x=56,\:y=36

Step-by-step explanation:

Let 'x' and 'y' be the two numbers

As the sum of the two numbers is 92.

so

x+y = 92

Given that One-eighth of the larger number plus one-third of the smaller number is 19.

so

\frac{1}{8}x\:+\:\frac{1}{3}y=19

now solving both equations to determine the numbers 'x' and 'y'.

\begin{bmatrix}\frac{1}{8}x+\frac{1}{3}y=19\\ x+y=92\end{bmatrix}

\mathrm{Multiply\:}\frac{1}{8}x+\frac{1}{3}y=19\mathrm{\:by\:}8\:\mathrm{:}\:\quad \:x+\frac{8}{3}y=152

\begin{bmatrix}x+\frac{8}{3}y=152\\ x+y=92\end{bmatrix}

x+y=92

-

\underline{x+\frac{8}{3}y=152}

-\frac{5}{3}y=-60

\begin{bmatrix}x+\frac{8}{3}y=152\\ -\frac{5}{3}y=-60\end{bmatrix}

solve for y

-\frac{5}{3}y=-60

-5y=-180

\mathrm{Divide\:both\:sides\:by\:}-5

\frac{-5y}{-5}=\frac{-180}{-5}

y=36

\mathrm{For\:}x+\frac{8}{3}y=152\mathrm{\:plug\:in\:}y=36

x+\frac{8}{3}\cdot \:36=152

x=56

Thus, the numbers 'x' and 'y' are:

x=56,\:y=36

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