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Answer:</h2>
<h2>Step-by-step explanation:</h2>
<h2>Given :</h2>
<h2>To Find :</h2>
<h2>Solution :</h2>
We have to add 1 in numerator and -10 in denominator because
![\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]](https://tex.z-dn.net/?f=%20%5Ctt%20%5Cfrac%7B8%7D%7B101%7D%20%2C%20%5Cfrac%7B9%7D%7B91%7D%20%2C%20%5Cfrac%7B10%7D%7B81%7D%20%2C%20%5Cfrac%7B11%7D%7B71%7D%20...%5BGiven%5D)
The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.
Hi there! I can help you! 8 + (-9) + (-2). When adding negative integers, you have to subtract. 8 - 9 is -1 and -1 - 2 is -3. You would have to start at 8 and go to the left 11 times to land on -3. The sum to the problem is -3.
replace the numbers given for x & y so
the equation becomes 3*(-3) + 2*(-4) =
3*-3 = -9
2*-4 = -8
-9 + -8 = -17
His brothers have 4 games
He had 10 games
So in total there are 14 games
And if there are 2 cases and each one had the same amount, then in each one there would be 14÷2=7
In each case, there are 7 games.
Answer:what do you need help with
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