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2 years ago

How many minutes are there in a day?

Mathematics

2 answers:

RoseWind [281]2 years ago

5 0

1440

because yea

hehehehehehehehehee

makvit [3.9K]2 years ago

5 0

Answer:

1440 min

24 hours × 60 min

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Molly's Custom Kitchen Supplies sells handmade forks and spoons. It costs the store $1.70 to buy the supplies to make a fork and

Alika [10]

Answer:

3 spoons were sold last April

Step-by-step explanation:

Let x represent the total number of forks that they made last month.

Let y represent the total number of spoons that they made last month.

It costs the store $1.70 to buy the supplies to make a fork. This means that the cost of making x spoons will be 1.70×x = 1.7x

It costs the store $1.30 to buy the supplies to make a spoon. This means that the cost of making y spoons will be 1.30×y = 1.3y.

Total cost of making x forks and y spoons is 1.7x + 1.3y

Last April Molly's Custom Kitchen Supplies spent $37.90. This means that

1.7x + 1.3y = 37.90 - - - - - - - - - - 1

The store sells forks for $5.60. This means that the total amount for x forks will be 5.60×x = 5.6x

The store sells spoons for $5.40. This means that the total amount for y spoons will be 5.40×y= 5.4y.

Total amount made from selling x forks and y spoons is 5.6x + 5.4y. They sold the finished products for a total of $147.20. This means that

5.6x + 5.4y = 147.20 - - - - - - - -2

Multiplying equation 1 by 5.6 and equation 2 by 1.7, it becomes

9.52x + 7.28y = 212.24

9.52x + 9.18y = 250.24

Subtracting

- 1.9x = - 38

x = - 38/- 1.9

x = 20

Substituting x = 20 into equation 1, it becomes

1.7×20 + 1.3y = 37.90

34 + 1.3y = 37.90

1.3y = 37.90- 34 = 3.9

y = 3.9/1.3

y = 3

5 0

3 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.

andreyandreev [35.5K]

The products of the polynomials are:

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
(x - y) * (x + 3y) = x² + 2xy + 3y²
(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18
(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6
(x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9) = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²