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ikadub [295]
3 years ago
8

How can I get the area of the shaded region?

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Let's work on the triangle first.  The x intercept of 2y=27-3x is

0 = 27 - 3x

3x = 27

x = 9

So A(9,0)

B is the meet of 2y=27-3x and y=3x

2y=27-y

3y=27

y=9

y is the height of OAB; we don't really need x

Area(OAB) = \frac 1 2 (9)(9) = \frac{81}{2} = 40.5

Now we have to subtract

\displaystyle \int_0^9 (3x - x^{\frac 3 2})dx = \frac 3 2 x^2 - \frac 2 5 x^{\frac 5 2} \bigg|_0^9 = \frac 3 2 (9^2) - \frac 2 5 (9^{\frac 5 2}) = \frac{1}{2}(243) - \frac 2 5 (243) = 24.3

Area = 40.5 - 24.3 = 16.2

Answer: 16.2


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PLEASE HELP!!! very confused
Leni [432]

Answer:

Step-by-step explanation:

The vertices lie on the x-axis, as is determined by their coordinates. This makes the center of this hyperbola (0, 0) because the center is directly between the vertices. The fact that the foci also lie on the x-axis tells us that this is the main axis. What this also tells us is which way the hyperbola "opens". This one opens to the left and the right as opposed to up and down. The standard form for this hyperbola is:

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 and so far we have that h = 0 and k = 0.

By definition, a is the distance between the center and the vertices. So a = 5, and a-squared is 25. So we're getting there. Now here's the tricky part.

The expressions for the foci are (h-c, k) and (h+c, k). Since we know the foci lie at +/-13, we can use that to solve for c:

If h+c = 13 and h = 0, then

0 + c = 13 and c = 13.

We need that c value to help us find b:

c^2=a^2+b^2 and

13^2=5^2+b^2 and

169=25+b^2 and

144=b^2 so

b = 12. Now we're ready to fill in the equation:

\frac{x^2}{25}-\frac{y^2}{144}=1 and there you go!

3 0
3 years ago
How many different possible meal outcomes are there if you're having one item each from the main course, sides, and drink menu?
lyudmila [28]
Answer: 64
Explanation: 4^3
6 0
3 years ago
The mean age of Mr Jasmi,Miss Haslinda and their three children is 38 years. The mean age of their three children is 18 years. C
DedPeter [7]
Answer: 68

Explanation:

Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children

We can write:
(x + y + a + b + c)/5 = 38

But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54

Substitute this value to our first equation

(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136

Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2

But x + y = 136

=> mean age = 136/2 = 68
4 0
3 years ago
a) The quadratic 3x^2-12x-11 can be written in the form 3(x+a)^2+b. Find the values of a and b. b) Given that the solutions of t
LenKa [72]

Answer:

Step-by-step explanation:

a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23

so  a= -2 ,b= -23

b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=

2+V69/9=2+V23/3

c=2, d= 23/3

5 0
3 years ago
Simplify the following expression:<br> -8 (5b + 2) -7 ( b-5)
RUDIKE [14]

Answer:

-8(5b+2)-7(b-5)

first, use distributive property to get:

-40b-16-7b+35

then, use combine like terms to simplify:

-47b+19

that's your answer!

:)))))))))

3 0
3 years ago
Read 2 more answers
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