All categories

3 years ago

The measures of the angles of a triangle are shown in the figure below. Find the

Mathematics

1 answer:

dimaraw [331]3 years ago

6 0

Answer:

318.6

Step-by-step explanation:

(3x-9) + (x+15) = 180

3x (x+15) -9 (x+15)

4x + 45x - 9x + 6 = 180

40x + 6 = 180

40x = 180 - 6

40x = 174

x = 4.34

(3x-9) = 4.34 * 3x-9 = 4.02

(x+15) = 4.34 + 15 = 19.34

180 - (4.02 + 19.34)

= 180 - 23.36

= 156.64

hope this answer helps!!

You might be interested in

Help me with 24,26,28, and 30 please.

Novay_Z [31]

24)
The number 1/10 can be expressed as a decimal by dividing the top number by the bottom.
1/10=0.1
0.8>0.1
0.8>1/10

26)
The number 3/5 can also be expressed as a decimal, using the method I described for 24.
3/5=0.6
0.6>0.35
3/5>0.35

28)
The number 2/5 can also be expressed as a decimal.
2/5=0.4
0.4>0.3
2/5>0.3

30)
The number 1/6 cannot be expressed as a decimal. So, express 0.2 as a fraction.
0.2=2/10=1/5
1/5=6/30
1/6=5/30
6/30>5/30
0.2>1/6

Hope this helps!

8 0

3 years ago

Given the equation y = 3x − 4, what is the value of x when y = 5? A) 3 B) 6 C) 9 D) 12

Dmitrij [34]

Answer:

A. 3

Step-by-step explanation:

The answer would be A because 3 times 3 is 9 and 9-4=5 which is the value o f y. 3x-4=5

add 4 to both sides: 3x=5+4

simplify: 5+4=9

divide both sides by 3: x= 9/3

simplify 9/3 to 3:

x= 3

hope this helps!!

7 0

3 years ago

Help pls, will mark brainliest

BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be ${\sf T_n}$ is given by ;

${\boxed{\bf T_{n}=T_{1}+(n-1)d}}$

Where , <u>d</u> is the common difference

Now , here we are given with ;

${\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}$

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

${: \implies \quad \sf T_{1}+(5-1)d=T_{5}}$

Putting the values and transposing 1st term to RHS , we have ;

${: \implies \quad \sf 4d = -4-8}$

${: \implies \quad \sf d=-\dfrac{12}{4}}$

${: \implies \quad \sf d=-3}$

Now , as we got the common difference , so we can find out the missing terms now ;

${: \implies \quad \sf T_{2}= T_{1}+(2-1)d}$

${: \implies \quad \sf T_{2}= 8 +d}$

${: \implies \quad \sf T_{2}= 8-3}$

${: \implies \quad \bf \therefore \: T_{2}= 5}$

Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

${: \implies \quad \sf T_{3}= 8 +2d}$

${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

${: \implies \quad \sf T_{4}= T_{1}+(4-1)d}$

${: \implies \quad \sf T_{4}= 8 +3d}$

${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

8 0

3 years ago

The slope of the line below is -1. write the point-slope equation of the line using the coordinates of the labeled point.

omeli [17]

Answer:

y+9=-1(x-4)

Step-by-step explanation:

Point Slope Form is:

$y-y_1=m(x-x_1)$

When:

'm' is the slope.

$(x_1,y_1)$ is the coordinate.

We are given the slope of -1 and the coordinate of (4,-9).

So:

$m=-1\\x_1=4\\y_1=-9$

Using the information and replacing the values we get:

$y+9=-1(x-4)$

So, the line equation in point slope form should be: y+9=-1(x-4)

<em>Brainilest Appreciated. </em>

5 0

3 years ago

Read 2 more answers

5 points

azamat

Step-by-step explanation:

it so easy bro 5.5 ok bro.

3 0

3 years ago