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kupik [55]
3 years ago
13

QUESTION 1

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0
This is true because the system of equations that has solutions is called consistent.
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Choose the function with the largest constant of variation? A 2-column table with 5 rows. Column 1 is labeled x with entries 1,
Zielflug [23.3K]

Answer:

A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.

Step-by-step explanation:

?

3 0
3 years ago
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How do I do B I need it by today
Schach [20]
One etility later hahahha
4 0
3 years ago
Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3
Serhud [2]

Answer:

e^{3t}(2t+5t^{2})

Step-by-step explanation:

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem:L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]

Separate the fraction in a sum:

e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])

The formula for this is:

L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}

Modify the expression to match the formula.

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])

Solve

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )

6 0
3 years ago
Help is needed folks plz will give brainiest!
irina1246 [14]

Answer:

I belive the answer is F

Step-by-step explanation:

In question/ option F it tells us that she started with 12 bannanas before getting 4 more bunchs, the question then asks how many bannanas were in each bunch, which then added plus 12 would of gotten you 32 bannans.

6 0
3 years ago
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The triangle has an area of 7\frac{7}{8}7 8 7 ​ cm2 and a base of 5\frac{1}{4}5 4 1 ​ cm. What is the length of h? Explain your
motikmotik

Answer:

<h3>3cm</h3>

Step-by-step explanation:

Area of a triangle = 1/2 * base * height

Given

Area = 7 7/8cm²

Base = 5 1/4 cm

Required

Height of the triangle

Substitute;

7 7/8 = 1/2 * 5 1/4 * Height

63/8 = 1/2 * 21/4 * h

63/8 = 21H/8

63 = 21H

H = 63/21

H = 3cm

Hence the length of h is 3cm

7 0
3 years ago
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