Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
y = e^x
Step-by-step explanation:
The fastest way to do this is to use a graphing calc or an online graphing platform and check to see which graph matches the one given.
Answer:
1) 2019
2) 120-50=70
3) 2018
4) 100
5) 2018
6) 120-80=40
7) 2018
Step-by-step explanation:
1) 2019
2) 120-50=70
3) 2018
4) 100
5) 2018
6) 120-80=40
7) 2018
A)Add 3 and the continue to add 2 more to three each time to get the next number
B)add 1 and add one to the number one each time to get the the next number
Answer:
2 400 000
Step-by-step explanation:
is that right? not sure wut u were looking for
