3 x 7 because three, seven times is 21
B is the Y-intercept or where the graph crosses the y-axis. they provide you with a few things which can help you figure this out. they give you the values of x and y in a table
X | Y
2 | -5
4 | -9 The difference between each Y value is 4...so, I add 4 to the -5
6 | -13 and get -1...going up another value for the X would be at 0. This leaves me with an ordered pair of (0,-1).....thus, the value of b is -1.
Answer:
um
Step-by-step explanation:
um why did you spell a lot ????
Answer:
45%
Step-by-step explanation:
If it not right im sorry that is a very odd question
Area inside the semi-circle and outside the triangle is (91.125π - 120) in²
Solution:
Base of the triangle = 10 in
Height of the triangle = 24 in
Area of the triangle = 

Area of the triangle = 120 in²
Using Pythagoras theorem,




Taking square root on both sides, we get
Hypotenuse = 23 inch = diameter
Radius = 23 ÷ 2 = 11.5 in
Area of the semi-circle = 

Area of the semi-circle = 91.125π in²
Area of the shaded portion = (91.125π - 120) in²
Area inside the semi-circle and outside the triangle is (91.125π - 120) in².