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amid [387]
3 years ago
14

Find two unit vectors orthogonal to a=⟨2,−2,−3⟩a=⟨2,−2,−3⟩ and b=⟨3,2,2⟩b=⟨3,2,2⟩ enter your answer so that the first non-zero c

oordinate of the first vector is positive.
Mathematics
1 answer:
Ronch [10]3 years ago
8 0
We need the cross product of the two vectors.
a x b
=<2,-2,-3> x <3,2,2>
=
i    j   k
2 -2 -3
3  2  2
=<-4+6, -(4+9), 4+6>
=<2,-13,10>
The second vector is obtained by reversing the direction, namely <-2,13,-10>
Thus the two vectors are <2,-13,10> and <-2,13,-10>.
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The median and mean of these numbers:
aleksandr82 [10.1K]

Answer:

Mean : ≈ 12.7

Median: ≈ 13.5

Step-by-step explanation:

To find the mean you must add all the numbers and divide by the # of numbers in the set.

8+12+13+14+14+15 = 76

76/6 ≈ 12.7

To find the median you have to order the numbers from least to greatest, the middle number should be the median, but in this case two numbers are in the middle.

8, 12, 13, 14, 14, 15

So you have to add 14 and 13, which is 27.

Then divide by 2 which is ≈ 13.5

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=7%5Csqrt%7B3%7D%20%2B%5Csqrt%7B63" id="TexFormula1" title="7\sqrt{3} +\sqrt{63" alt="7\sqrt{3}
mezya [45]

Answer:7√3 + 3√7

Step-by-step explanation:

7√3 + √63

=> 7√3 + √(7×9)

=> 7√3 + (√7 × √9)

=> 7√3 + 3√7

8 0
3 years ago
Find the missing side of this right
navik [9.2K]

Answer:

x = 13

Step-by-step explanation:

First start with the blank equation

a^{2} + b^{2} = c^{2}

Plug in the legs and hypotenuse. Remember c squared is always the hypotenuse.

5^{2} + 12^{2} = c^{2}

Then solve

25 + 144 = c^{2}

169 =c^{2}

\sqrt{169} = \sqrt{c^{2} }

c = 13

3 0
3 years ago
Simplify 4x + 7 + 11x
ozzi
15x plus 7
This is because you just simplify the like terms
5 0
4 years ago
Simplify the expression
erastova [34]

Answer : A

We need to simplify the given expression

Lets factor numerator first

2x^2-5x-3 =(2x+1)(x-3)

x^2+8x+15 =(x+5)(x+3)

Now we factor the denominator

x^2+x-20 =(x+5)(x-4)

2x^2+9x+4 =(2x+1)(x-4)

Now we simplify it

\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}

Now cancel out same factors. so we left with

\frac{(x+3)(x-3)}{(x+4)(x-4)} }

Now multiply the factors

\frac{x^2-9}{x^2-16} }



6 0
3 years ago
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