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2 years ago

Based on the data in the table what is the probability ricardo will spin blue on his next spin

Mathematics

1 answer:

klio [65]2 years ago

3 0

C:
Because if you add up all the spins you get 120
The spinner landed on blue 36 times out of those 120 spins...
So if you make it a fraction : 36/120
They are both divisible by 12 so you get : 3/10

Hope this helps! Any questions let me know :)

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You have 3/6 cup of brown sugar in your cupboard. The recipe for a dessert

Dmitry_Shevchenko [17]

Already have: 3/6 cups
need : 1/5
3/6 - 1/5=
15/30 - 6/30=
9/30=
3/10

so you wil have 3/10 of brown sugar left

3 0

3 years ago

A man realizes he lost the detailed receipt from the store and only has the credit card receipt with the after-tax total. If the

Ilia_Sergeevich [38]

$972.00/1.08 = Total pre-tax was $900

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3 years ago

If r = 4 and ^a8 = 100, what is the first term of the geometric sequence?

telo118 [61]

The first term of the geometric sequence is 0.0061

Step-by-step explanation:

The general form of geometric sequence is a, ar, ar²,ar³,.......

where,

a is the first term of the sequence.
r is the common ratio. Here, the common ratio r = 4.
The 8th term of the sequence is 100. Hence n = 8.

The formula to find the nth term of the geometric sequence is given by :

⇒ $n_{th} term = ar^{n-1}$

⇒ $8_{th}term = a\times4^{8-1}$

⇒ $100 = a \times 4^{7}$

⇒ $100 = a \times 16384$

⇒ $a = \frac{100}{16384}$

⇒ a = 0.0061

Therefore, the first term of the geometric sequence is 0.0061

6 0

3 years ago

Vick makes jewelry. She uses 42 beads for each necklace that she makes,and she has 500 beads. How many necklaces can she make? E

torisob [31]

He can make about 12 brackets

7 0

3 years ago

Read 2 more answers

Historically, a certain region has experienced 92 thunder days annually. (A "thunder day" is day on which at least one instance

DiKsa [7]

Answer:

We conclude that the mean number of thunder days is less than 92.

Step-by-step explanation:

We are given that Historically, a certain region has experienced 92 thunder days annually.

Over the past fifteen years, the mean number of thunder days is 72 with a standard deviation of 38.

Let $\mu$ = mean number of thunder days.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 92 days {means that the mean number of thunder days is more than or equal to 92}

Alternate Hypothesis, $H_A$ : $\mu$ < 92 days {means that the mean number of thunder days is less than 92}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of thunder days = 72

s = sample standard deviation = 38

n = sample of years = 15

So, test statistics = $\frac{72-92}{\frac{38}{\sqrt{15} } }$ ~ $t_1_4$

= -2.038

The value of z test statistics is -2.038.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -1.761 at 14 degree of freedom for left-tailed test.

Since our test statistics is less than the critical value of t as -2.038 < -1.761, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean number of thunder days is less than 92.

7 0

3 years ago