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Ad libitum [116K]
3 years ago
12

Work out these questions without a calculator and showing all working out

Mathematics
1 answer:
natima [27]3 years ago
3 0
1) 6÷0.2 = 30

If 6/2=3 then 6/0.2=30 as the decimal place shifts one place.

2)8÷0.1 = 80

8/1=8 so shift the decimal place over once to make 80.

3)9÷0.3 = 30

9/3=3 so shift the decimal place over once to get 30.

4)4÷0.04 = 100

4/4=1 so shift the decimal place over twice to get 100.

5)7÷0.002 = 3500

7/2=3.5 so shift the decimal place over three times to get 3500

6)0.718÷0.2 = 3.59

718/2=359 so shift the decimal over three places for the 0.718 and then back over once for the 0.2

7)0.0141÷0.003 = 4.7

141/3=47 so shift the decimal over our times for the 0.0141 and then back over three times for the 0.003

8)0.24÷0.012 = 20

24/12=2 so shift the decimal point over once twice for 0.24 then back over three times for 0.012

9)1.625÷0.0013 = 1250

1625/13=125 so shift the decimal point over three times for the 1.625 and then back four times for the 0.0013

10)47.1÷0.15 = 314

471/15=31.4 so shift the decimal point over once for the 47.1 and then back over twice for the 0.15.

Hope this helps :)
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kirza4 [7]

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3 years ago
The table shows the solution to the equation |2x − 3| − 1 = 2: Step 1 |2x − 3| = 2 + 1 Step 2 |2x − 3| = 3 Step 3 2x − 3 = 3 or
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There are 4 white marbles and 6 blue marbles in a bag. Jamie will randomly pick two marbles out of the bad without replacing the
zepelin [54]

Step-by-step explanation:

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8 0
3 years ago
What is 16 tens + 4 ones
aalyn [17]
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5 0
3 years ago
Read 2 more answers
You have 42,784 grams of a radioactive kind of curium. If its half-life is 18 years, how much will be left after 72 years?
s344n2d4d5 [400]

Answer:

2,674.14 g

Step-by-step explanation:

Recall that the formula for radioactive decay is

N = N₀ e^(-λt)

where,

N is the amount left at time t

N₀ is the initial amount when t=0, (given as 42,784 g)

λ = coefficient of radioactive decay

  = 0.693 ÷ Half Life

  = 0.693 ÷ 18

  = 0.0385

t = time elapsed (given as 72 years)

e = exponential constant ( approx 2.7183)

If we substitute these into our equation:

N = N₀ e^(-λt)

= (42,787) (2.7183)^[(-0.0385)(72)]

= (42,787) (2.7183)^(-2.7726)

=  (42,787) (0.0625)

= 2,674.14 g

6 0
3 years ago
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