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laiz [17]
3 years ago
8

(15-3)÷12+1How to divide this without using a remainder?​

Mathematics
2 answers:
Julli [10]3 years ago
8 0

Answer:

If you solved this, it wouldn't have a remainder. First you would solve the numbers in the parenthesis, (15 - 3), which is 12. Now it should look like, 12 ÷ 12 + 1. Next you divide 12 by 12 and that equals 1. And all you need to do now is add 1 + 1, which is 2. So your answer will be 2.

Ivanshal [37]3 years ago
5 0

Answer:

2

Step-by-step explanation:

To be able to solve this equation, you would use PEMDAS. This stands for the order of operations, and which order you would do them in.  P stands for parenthesis, E stands for exponents, M stands for multiplication, D stands for division, A stands for addition, and S stands for subtraction. Using this order, you would solve what is inside the parentheses first. So, 15-3 is 12. Once this piece is solved, you would have 12÷12+1. Then, since you don't have any exponents or multiplication, you would skip to division. 12 ÷ 12 is 1. So then your equation would be: 1+1. 1+1 is equal to 2. So your answer is 2! There is not remainder in the solution of this problem.

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I think of a number , multiply it by 3, add 4 and square the result
bazaltina [42]

Answer:

{(3x + 4)}^{2}

Step-by-step explanation:

<em>thinked</em><em> </em><em>number</em><em> </em><em>=</em><em> </em><em>x</em>

<em>multiply</em><em> </em><em>by</em><em> </em><em>3</em>

<em>x \times 3 \\ =  3x</em>

<em>add</em><em> </em><em>4</em><em> </em>

<em>3x + 4</em>

<em>square</em><em> </em><em>the</em><em> </em><em>result</em>

<em>{(3x + 4)}^{2}</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em>brainliest</em><em> </em><em>appreciated</em>

<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>

4 0
3 years ago
Read 2 more answers
When measuring the length a and the width b of a rectangle, it was found that 5.4&lt; a&lt; 5.5 and 3.6&lt; b&lt; 3.7 (in centim
leva [86]

Answer:

The possible values of the perimeter of the rectangle is between 18 and

18.4 cm ⇒ [18 < perimeter of rectangle < 18.4] cm

Step-by-step explanation:

* Lets explain how to solve the problem

- The perimeter of any quadrilateral is the sum of the length of its

  four sides

- The rectangle is a quadrilateral with each two opposite sides are

  equal in lengths, then its perimeter = 2l + 2w, where l, w are its

  length and width

∵ The the length of the rectangle is a

∵ 5.4 < a < 5.5 cm

∵ The perimeter of the rectangle = 2a + 2b

- Lets multiply the inequality by 2

∴ 5.4 × 2 < a × 2 < 5.5 × 2

∴ 10.8 < 2a < 11 ⇒ (1)

∵ The width of the rectangle is b

∵ 3.6 < b < 3.7 cm

- Lets multiply the inequality by 2

∴ 3.6 × 2 < b × 2 < 3.7 × 2

∴ 7.2 < 2b < 7.4 ⇒ (2)

- <u><em>Add inequalities (1) and (2)</em></u>

∵     10.8 < 2a < 11

  +   7.2 < 2b < 7.4

∴  18 < 2a + 2b < 18.4

∵ 2a + 2b represents the perimeter of the rectangle

∴ The possible values of the perimeter of the rectangle is between

  18 and 18.4 cm ⇒ [18 < perimeter of rectangle < 18.4] cm

7 0
3 years ago
Landen has his daily video gaming time each day for 7 days. But one day he plays and extra 50 minutes. His total video playing t
mojhsa [17]

Answer:

im thinking 25 or 24

Step-by-step explanation:

sorry if i made you get it wrong

8 0
3 years ago
Norman bought 5/6 pounds of cookies. He ate 3/5 cookies. What was the weight of the cookies he ate
schepotkina [342]

Answer:

Half a pound.

Step-by-step explanation:

To find the number of pounds he ate, multiply the fractions.

\frac{5}{6}*\frac{3}{5} = \frac{15}{30}=\frac{1}{2}

He ate 1/2 a pound.

8 0
4 years ago
The sum of two consecutive integers is 65. what are the two integers? show steps please.
Gnoma [55]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

\triangle~\fbox{\bf{KEY:}}

  • Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.

Let the first integer be x, and let the second integer be x+1.

Their sum is 65. Let's set up our equation:

\longmapsto\sf{x+x+1=65}

Combine like terms:

\longmapsto\sf{2x+1=65}

Subtract 1 from both sides of the equal sign:

\longmapsto\sf{2x=64}

Divide both sides by 2:

\longmapsto\sf{x=32}

To find the second integer, subtract the first integer from the sum of the two integers:

\longmapsto\pmb{65-32}

\longmapsto\pmb{33}

The integers are: 33 and 32.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

7 0
2 years ago
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