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Vilka [71]
3 years ago
11

Two tracking stations are on the equator 158 miles apart. A weather balloon is located on a bearing of N42°E from the western st

ation and on a bearing of N14°W from the eastern station. To the nearest tenth of a mile, how far is the balloon from the western station? *

Mathematics
2 answers:
Alinara [238K]3 years ago
7 0

Answer:

199.38

Step-by-step explanation:

To better understand the problem I leave an associated graph.

We must calculate the distance of AC, we know AB

AB = 158 miles.

Now we will apply the law of sine where:

AB / sin (° ACB) = AC / sin (° ABC)

We know the ° ABC = 14 °, the statement gives us the ° CAB = 90 ° - 38 ° = 52 °

Now assuming that within a triangle all the angles must add up to 180 °, then

° ACB = 180 ° - 52 ° - 14 ° = 114 °

Solving for AC:

AC = (AB * sin (° ABC)) / sin (° ACB)

AC = (158 * sin (14 °)) / sin (114 °)

AC = 199.38

Therefore the distance between the balloon from the western station is 199.38 miles

Alisiya [41]3 years ago
7 0

Answer:

184.9 miles

Step-by-step explanation:

The image attached will provide the necessary diagram and better explanations

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B, D, D, B, C

Step-by-step explanation:

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We know this because, if we reorganize the equation into the standard form  y = mx + b, we get y = -(x²) + 1. This means that for any value we substitute for x, y will always be negative. The answer is B.

2) To find the zeroes of this function, we just have to see which answer makes the function, well, zero.

We have the equation y = (-16t - 2) (t - 1)

We set the equation equal to zero like this:

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We also know that anything multiplied <em>by</em> zero will <em>equal</em> zero, so:

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The zeroes are when y = 0, so the zeroes (which are 1 and -1/8 from the last problem) mean that the height is also at zero (which is the ground).

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y = (-16(0) - 2) (0 - 1)

y = (-2) (-1)

y = 2

So, the correct answer is B, 2 feet.

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frutty [35]
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