2 years ago

What is the equation of the line that passes through (-2, 4) and (4, 5)

Mathematics

1 answer:

vampirchik [111]2 years ago

8 0

Answer:

y=1/6x+13/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(5-4)/(4-(-2))

m=1/(4+2)

m=1/6

y-y1=m(x-x1)

y-4=1/6(x-(-2))

y-4=1/6(x+2)

y=1/6x+2/6+4

y=1/6x+1/3+4

y=1/6x+1/3+12/3

y=1/6x+13/3

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Answer:

see below

Step-by-step explanation:

If suffices to look at the last term. It must simplify to 4/(3w²), so the exponents of z must match in numerator and denominator, and the ratio of constants must reduce to 4/3.

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