2 years ago

What is the equation of the line that passes through (-2, 4) and (4, 5)

Mathematics

1 answer:

vampirchik [111]2 years ago

8 0

Answer:

y=1/6x+13/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(5-4)/(4-(-2))

m=1/(4+2)

m=1/6

y-y1=m(x-x1)

y-4=1/6(x-(-2))

y-4=1/6(x+2)

y=1/6x+2/6+4

y=1/6x+1/3+4

y=1/6x+1/3+12/3

y=1/6x+13/3

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Consider the square root function f(x) = sqrt x + 2 + 1 to complete the table of values below. find each missing value and then

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Given the function :

$f(x)=\sqrt[]{x+2}+1$

We need to find each missing value

Given x = -3 , -2 , -1 , 2 , 7

So, substitute with each value of x to find the corresponding value of f(x)

$x=-3\rightarrow f(x)=\sqrt[]{-3+2}+1=\sqrt[]{-1}+1$

So, there is no value for f(x) at x = -3 (the function undefined because the square root of -1)

$\begin{gathered} x=-2\rightarrow f(x)=\sqrt[]{-2+2}+1=\sqrt[]{0}+1=0+1=1 \\ \\ x=-1\rightarrow f(x)=\sqrt[]{-1+2}+1=\sqrt[]{1}+1=1+1=2 \\ \\ x=2\rightarrow f(x)=\sqrt[]{2+2}+1=\sqrt[]{4}+1=2+1=3 \\ \\ x=7\rightarrow f(x)=\sqrt[]{7+2}+1=\sqrt[]{9}+1=3+1=4 \end{gathered}$

the graph of the function and the points will be as shown in the following image :