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Andreyy89
3 years ago
9

ABCD is a rhombus. Given only the choices below, which properties would you use to prove AEB ≅ DEC by SAS?

Mathematics
1 answer:
Nitella [24]3 years ago
4 0
"<span>The diagonals bisect each other" is the one property among the following choices given in the question that you would </span><span>use to prove AEB ≅ DEC by SAS. The correct option among all the options that are given in the question is the second option. I hope that this is the answer that has actually come to your desired help.</span>
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Solve for Xin the equation x^2-12+36=90
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X= + or- square root 66 i solved using the pq formula but u can also use the quadratic formula as well and the square root formula but I'ma show u how to solve it with pq it's on this image hope it helps and mark me brainliest

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A rectangle has an area of 2x2 - 19x +45 ft? What are the dimensions of the rectangle? (hint: factor)​
makkiz [27]
I think the answer is (2x - 9)(x - 5)
7 0
3 years ago
Plz help me I'm too Du-mb
Mekhanik [1.2K]

Answer:

5

Step-by-step explanation:

You must have x alone

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3 years ago
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The first term of a geometric series is -3, the common ratio is 6, and the sum of the series is -4,665. Using a table of values,
tamaranim1 [39]

Answer:

Option A. 5

Step-by-step explanation:

From the question given above, the following data were obtained:

First term (a) = –3

Common ratio (r) = 6

Sum of series (Sₙ) = –4665

Number of term (n) =?

The number of terms in the series can be obtained as follow:

Sₙ = a[rⁿ – 1] / r – 1

–4665 = –3[6ⁿ – 1] / 6 – 1

–4665 = –3[6ⁿ – 1] / 5

Cross multiply

–4665 × 5 = –3[6ⁿ – 1]

–23325 = –3[6ⁿ – 1]

Divide both side by –3

–23325 / –3 = 6ⁿ – 1

7775 = 6ⁿ – 1

Collect like terms

7775 + 1 = 6ⁿ

7776 = 6ⁿ

Express 7776 in index form with 6 as the base

6⁵ = 6ⁿ

n = 5

Thus, the number of terms in the geometric series is 5.

8 0
3 years ago
Identify the translation of the figure with the vertices P(−4,−5), L(1,−7), and K(−9,8), along the vector &lt;−6, 3&gt;.
jarptica [38.1K]

Answer:

P ′(−10, −2), L ′(−5, −4), K ′(−15, 11)

Step-by-step explanation:

The translation vector, ⟨−6,3⟩, can be used to derive a rule for the translation of the coordinates: (x,y)→(x−6,y+3).

Apply the rule to translate each of the three preimage vertices to the image vertices.

P(−4,−5)→P'(−10,−2)

L(1,−7)→L'(−5,−4)

K(−9,8)→K'(−15,11)

Therefore, P'(−10,−2), L'(−5,−4), N'(−15,11) is the translation of the figure with the vertices P(−4,−5), L(1,−7), and K(−9,8), along the vector ⟨−6,3⟩.

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2 years ago
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