Answer:
Yes number 5 is, they are proportional because y is coresponding to x by multiplying by 1/5
No number 6 isn't, you can't go from 3 to 1 and 7 to 3
Answer:
1. 13+10i
2. 28-(-4i)
3. -14-1i
4. 4 -i
5. 15+ 10i
6.8 - 5i^2
Step-by-step explanation:
The number of buckets is directly proportional to the area and the thickness of the wall and inversely proportional to the amount of paint. Mathematically, we can write:
n = k · (a · t) / p
where k is the proportionality constant which we do not know.
We can calculate k with the given data: 5 2-gallon buckets, area of 100 square feet and thickness 3 inches:
k = (n · p) / (<span>a · t)
= (5 </span>· 2) / (100 · 3) = 0.0333
Now that we know the constant, we can calculate the area that can be painted with 8 2-gallon buckets if the thickness is 6 inches:
a = (n · p) / (k<span> · t)
= (8 </span>· 2) / (0.0333 · 6)
= 80 ft²
Please, note that we made sure to have the exact same units of measurements than the previous case.
Therefore, the correct answer is an area of 80 ft².
Sub for each other since both equals y
2x-3=y=2x+5
2x-3=2x+5
minus 2x oth sides
-3=5
false
no solution
(we can see that since slopes are same and y intercepts are differnt, the lines are paralell and therfor never intersect)
D. No solution
Q1. The answers are (–1, 8), (0, 7), (3, 18)
<span>–3x + y ≥ 7
</span>Let's go through all choices:
<span>(–2, –3)
</span>(-3) * (-2) + (-3) ≥ 7
6 - 3 ≥ 7
3 ≥ 7 INCORRECT
(–1, 8)
(-3) * (-1) + 8 ≥ 7
3 + 8 ≥ 7
11 ≥ 7 CORRECT
(0, 7)
(-3) * 0 + 7 ≥ 7
0 + 7 ≥ 7
7 ≥ 7 CORRECT
(1, 9)
(-3) * 1 + 9 ≥ 7
-3 + 9 ≥ 7
6 ≥ 7 INCORRECT
(3, 18)
(-3) * 3 + 18 ≥ 7
-9 + 18 ≥ 7
9 ≥ 7 CORRECT
Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes
</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80
Jude needs at least 4 small boxes on the shelf: x ≥ 4
Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16
x ≥ 4 can include x ≤ 16
So, y can be 0: y ≥ 0
