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Mathematics

1 answer:

MrRa [10]2 years ago

4 0

Discriminant b^2-4ac = (-9)^2 - 4*2*9 = 9
so there are 2 roots
because of the -9x and 9 they will both be positive

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tangare [24]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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zubka84 [21]

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Step-by-step explanation:

that's what I found. It would be better if u had more details in your question.

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creativ13 [48]

He should use the Pythagorean Theorem to find the missing length.

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3 years ago

Find all solutions in the interval [0,2pi). 2sin^2(x)=sin(x)

SIZIF [17.4K]

$2\sin^2 x =\sin x \\\\\implies 2 \sin^2 x - \sin x=0\\\\\implies \sin x(2 \sin x -1) =0\\\\\implies \sin x = 0~~\text{or}~~ 2 \sin x -1 =0\\\\\implies \sin x = 0~~ \text{or}~ ~ \sin x = \dfrac 12\\\\\text{For}~~ \sin x = 0\\\\x=n\pi \\\\\text{In the interval,}~~[0, 2\pi)\\\\x=0, \pi\\\\\text{For}~~ \sin x = \dfrac 12\\\\x=n\pi+(-1)^n \dfrac{\pi}6 \\\\\text{In the interval,}~~[0, 2\pi)\\\\x=\dfrac{\pi}6,~ \dfrac{5\pi}6\\\\\text{Hence,}~ x = 0,~\pi,~ \dfrac{\pi}6, ~\dfrac{5 \pi}6$

4 0

2 years ago

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