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-Dominant- [34]
3 years ago
14

What is

le="9 \frac{1}{6} - 5 \frac{5}{6} " alt="9 \frac{1}{6} - 5 \frac{5}{6} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
lesya [120]3 years ago
5 0
First,, we need to convert the first mixed number to an improper fraction.
\frac{9X6+1}{6}
Multiply the numbers.
\frac{54+1}{6}
Add the numbers together to finish the mixed number and add it back into the expression.
\frac{55}{6} - 5\frac{5}{6}
Now use the same process I showed above to convert the second mixed number to an improper fraction.
\frac{55}{6} -  \frac{35}{6}
Now subtract the two fractions to find your final answer.
\frac{10}{3}
This means that your answer is going to be \frac{10}{3} or 3\frac{1}{3} simplified.
Let me know if you have any further questions.
:)
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5 0
3 years ago
Read 2 more answers
Which of the following expressions is equivalent to 32 ÷ 4• 4 ÷ 2 • 2?​
mel-nik [20]

Answer:

128

Step-by-step explanation:

32 ÷ 4• 4 ÷ 2 • 2

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128

6 0
3 years ago
Simplify: |3 – 10| – (12 / 4 + 2)^2<br> 0 - 32<br> O – 18<br> O3<br> 0 - 6
MakcuM [25]

Answer:

-18

Step-by-step explanation:

Simplify: |3 – 10| – (12 / 4 + 2)^2

|3 - 10| - (\frac{12}{4}  + 2)^2\\\\|-7|-(\frac{12}{4}  + 2)^2 < == absolute\ numbers\ are\ always\ positive\\\\7-(3+2)^2 < ==add\ numbers\ in\ parenthesis\\\\7-5^2 < ==square\ the\ number\ (5)\\\\7-25 < ==add\ numbers\\\\-18 < ==final\ answer

Hope this helps!

6 0
2 years ago
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The quadratic equation ax^2+32x+c=0 has exactly one solution. If a+c=130, and a&gt;c, find the ordered pair (a,c).
vitfil [10]
Ie 32^2 - 4ac=0 so ac=256 and a+c=130 
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4 0
4 years ago
Find the balance in the account. $2,500 principal earning 4%, compounded quarterly, after 4 years
Helen [10]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad  \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2500\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &4 \end{cases} \\\\\\ A=2500\left(1+\frac{0.04}{4}\right)^{4\cdot 4}\implies A=2500(1.01)^{16}\implies A\approx 2931.4466123

3 0
4 years ago
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