At
, the volume of the gas is V=22 L.
At temperature
, the volume of the gas is (22+225) L.
This means that if we increase the temperature by
degrees:
the volume of the gas is
![V=22 + 225 k [L]](https://tex.z-dn.net/?f=V%3D22%20%2B%20225%20k%20%5BL%5D)
(1)
Since T=k, we can rewrite eq.(1) as
![V= 22 + 225 T [L]](https://tex.z-dn.net/?f=V%3D%2022%20%2B%20225%20T%20%5BL%5D)
which gives the expression for the volume of the gas in liters, as a function of the temperature T in Celsius.
Answer: $129
Step-by-step explanation:
Answer:
The answer in the explanation
Step-by-step explanation:
we have
Step 1
Determine the least common denominator (LCD) of all fractions in the equation
The LCD is equal to
Step 2
Multiply both sides of the equation by 6 to remove the fractions
![6[\frac{1}{3}x-5]=6[\frac{5}{2}x-\frac{2}{3}]](https://tex.z-dn.net/?f=6%5B%5Cfrac%7B1%7D%7B3%7Dx-5%5D%3D6%5B%5Cfrac%7B5%7D%7B2%7Dx-%5Cfrac%7B2%7D%7B3%7D%5D)
Step 3
Solve for x
Group terms
Combine like terms
Answer:
One:225
Tenth: 225.2
Hundredth: 225.29
Step-by-step explanation:
In pretty sure this is right i apologize if not I havent done this in a couple of years.
Answer:
the origin, (0, 0)
Step-by-step explanation:
The coordinates of A' are 1/2 those of A, meaning each has been multiplied by the scale factor 1/2. When the dilated points are all the original points multiplied by the scale factor, the center of dilation is the origin.
_____
For center of dilation Q, the image of a point A after dilation by a factor of k is ...
A' = kA + (k-1)Q
Then for points A, A', and dilation factor k, the center of dilation can be found to be ...
(A' -kA)/(k-1) = Q
Here, that is ...
Q = ((-2, -2) -(1/2)(-4, -4))/(1/2 -1) = (0, 0)/(-1/2)
Q = (0, 0)
