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Oksana_A [137]
3 years ago
10

List the 6 congruency statements given triangle ABC is congruent to triangle DEF

Mathematics
2 answers:
Doss [256]3 years ago
5 0
The correct answer is A
fredd [130]3 years ago
4 0
It should be the first one
You might be interested in
А,
stepladder [879]
Hey I don’t understand
6 0
3 years ago
A box stall is a square or rectangular enclosure that can house one or more animals. Derek wants to construct a square box stall
stepladder [879]

Your answer is 550000!!!


Hope this helped!!!XD


Also can I get brainiest?XD


4 0
3 years ago
Quick I need to finish this and I still have more questions after
OLEGan [10]

Answer:

1\frac{1}{2} or 1.5

Step-by-step explanation:

Now we know it's a dilation.  So we can use any two points.  I chose V and V'.

V: (3,6)

V': (2,4)

So how we get from 6 to 4?

4(x)=6\\x=\frac{6}{4} \\x=1.5

You can tell it's 1.5 aswell because 4 times 1 is 4 and 4 times 0.5 is 2.  Add them to get 6.  

Therefore, the dilation factor is 1.5.

3 0
2 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

5 0
1 year ago
ABCD is a square of side 3, and E and F are the mid points of sides AB and BC respectively. What is the area of the quadrilatera
Dima020 [189]
Given : - Square ABCD with side 3.  E and F as midpoints.
To find : - area of EBFD

Solution : - We have, area of square ABCD = 3 x 3 = 9 units.

Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF

arDAE = 1/2 x base x height

=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25

arDFC = 1/2 x base x height 
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25

Thus, (ar) EBFD = arABCD - arDAE - arDCF

= 9 - 2.25 - 2.25

= 4.5 units.

Thus, area of quad EBFD is 4.5 units.  
7 0
3 years ago
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