Answer:
15.7
Step-by-step explanation:
Circumference= πd
d= Diameter
Answer:
y = (∛x)/3
Step-by-step explanation:
To undo the multiplication by 27, you multiply by its inverse:
(1/27)y = (1/27)(27x^3)
y/27 = x^3 . . . . . . . . . . . simplify
To undo the cube, you take the cube root:
(∛y)/(∛27) = ∛(x^3)
(∛y)/3 = x
Apparently, you want the inverse function, so you swap the variables:
y = (∛x)/3
_____
You can swap the variables at the beginning or end. It doesn't matter. If you do it at the beginning, you have ...
x = 27y^3
and you're solving for y. You use the same inverse operations that we used above.
5x + y = 15
y = -5x + 15
Substituting y= -5x+15 from first equation into second equation:
3x + 2y = 16
3x + 2·(-5x + 15) = 16
3x - 10x + 30 = 16
-7x + 30 = 16
7x = 30 - 16 = 14
x = 2
Substituting x=2 into the first equation:
5x + y = 15
5(2) + y = 15
10 + y = 15
y = 15 - 10
y = 5
So your final answers are x=2 and y=5.
Suppose the number is x, its reciprocal is 1/x
x+1/x=13/6
(x^2+1)/x=13/6
6(x^2+1)=13x
6x^2-13x+6=0
(3x-2)(2x-3)=0
x=2/3 or x=3/2
The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
