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Karo-lina-s [1.5K]
3 years ago
7

What two numbers has a lcm of 50

Mathematics
1 answer:
EleoNora [17]3 years ago
4 0
1 and 50
2 and 25
2 and 50
5 and 50
10 and 50
25 and 50

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1 point
WARRIOR [948]
59 is an outlier it's not in the 70s
8 0
3 years ago
8m +7=8m+5<br> PLEAE HELP ASAP
bixtya [17]

Answer: 0 = − 2, Is the answer I think. Sorry if it's wrong.

5 0
3 years ago
Geometric Series assistance
Levart [38]

we have been asked to find the sum of the series

\sum _{n=1}^5\left(\frac{1}{3}\right)^{n-1}

As we know that a geometric series has a constant ratio "r" and it is defined as

r=\frac{a_{n+1}}{a_n}=\frac{\left(\frac{1}{3}\right)^{\left(n+1\right)-1}}{\left(\frac{1}{3}\right)^{n-1}}=\frac{1}{3}

The first term of the series is a_1=\left(\frac{1}{3}\right)^{1-1}=1

Geometric series sum formula is

S_n=a_1\frac{1-r^n}{1-r}

Plugin the values we get

S_5=1\cdot \frac{1-\left(\frac{1}{3}\right)^5}{1-\frac{1}{3}}

On simplification we get

S_5=\frac{121}{81}

Hence the sum of the given series is \frac{121}{81}

5 0
3 years ago
What percent is 608 million of 845 million
boyakko [2]
In order to solve that, let's call 845 100%, as we're solving it terms of 845. 845 is 100%, then it follows that 8.45 is 1%. 

Now we can see how many 8.45's go into 608, which comes out to 71.95266...%, which can be rounded nicely to 72%

The million doesn't matter.
5 0
3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
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