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Bumek [7]
3 years ago
13

A regular- size cereal box is shaped like a rectangular prism. The length of the Box in 8 inches and the width is 2 inches. The

volume of the box is 176 cubic inches. A family size cereal box has double the volume of the regular- size box, with the same height and width. What is the length of the family- size cereal box? ​
Mathematics
1 answer:
attashe74 [19]3 years ago
7 0

Answer:

22 inches

Step-by-step explanation:

176÷16=11

11×2=22

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Solve the following equation, and check your solution. Be sure to show all work.
sweet-ann [11.9K]

<u>1. </u>Subtract 24 from both sides

-3x = -27 - 24

Simplify -27 - 24 to -51

-3x = -51

Divide both sides by -3

x = -51/-3

Two negatives make a positive

x = 51/3

Simplify 51/3 to 17

<u>x = 17</u>

<u>2.</u> Regroup terms

n/5 - 17 = 33

Add 17 to both sides

n/5 = 33 + 17

Simplify 33 + 17 to 50

n/5 = 50

Multiply both sides by 5

n = 50 * 5

Simplify 50 * 5 to 250

<u>n = 250</u>

3 0
3 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
2 years ago
What if it was for 20 months
olya-2409 [2.1K]

Answer:

dont really understand your question but 20 months is

608.334 days and 86.9049 months

6 0
2 years ago
Please help me with this and thank you
Anarel [89]

I think it’s D sorry if you get this wrong I also have to do my work

7 0
3 years ago
Given f(x) = x+2 and g(x) = x-4 solve for (fg)(x)
kirza4 [7]

Answer:  f(g(x)) = x - 2

<u>Step-by-step explanation:</u>

f(x) = x + 2            

g(x) = x - 4

f(g(x)) = f(x - 4) = (x - 4) + 2        <em>replaced x with x - 4</em>

                       = x - 2                 <em>simplified</em>

6 0
3 years ago
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