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andreyandreev [35.5K]
3 years ago
10

Al2Cl6 (266.7 g/mol) is made by treating scrap aluminum with chlorine gas. If a reaction is run with 270 g of aluminum and 710 g

of chlorine. Do the following calculations. Balance reaction equation is given below for your convenient.
2 Al (s) + 3 Cl2(g) → Al2Cl6(s)
a. Find the limiting reactant.
b. Find the theoretical yield of Al2Cl6
c. If mass of 469.0 g of Al2Cl6 was produced from the above reaction what was the percent yield for this reaction?
Chemistry
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

asdrtfguybhnjmk,l;.'/

Explanation:

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Which of the following processes have a ΔS < 0? Which of the following processes have a ΔS < 0? carbon dioxide(g) → carbon
Umnica [9.8K]

Answer:

All of the above processes have a ΔS < 0.

Explanation:

ΔS represents change in entropy of a system. Entropy refers to the degree of disorderliness of a system.

The question requests us to identify the process that has a negative change of entropy.

carbon dioxide(g) → carbon dioxide(s)

There is  a change in state from gas to solid. Solid particles are more ordered than gas particles so this is a negative change in entropy.

water freezes

There is  a change in state from liquid to solid. Solid particles are more ordered than liquid particles so this is a negative change in entropy.

propanol (g, at 555 K) → propanol (g, at 400 K)

Temperature is directly proportional to entropy, this means higher temperature leads t higher entropy.

This reaction highlights a drop in temperature which means a negative change in entropy.

methyl alcohol condenses

Condensation is the change in state from gas to liquid. Liquid particles are more ordered than gas particles so this is a negative change in entropy.

6 0
3 years ago
Freeze-drying is a process used to preserve food. If strawberries are to be freeze-dried, then they would be frozen to -80.00 °C
katrin2010 [14]

Answer:

1. 389 kJ; 2. 7.5 µg; 3. 6.25 days

Explanation:

1. Energy required

The water is converted directly from a solid to a gas (sublimation).

They don't give us the enthalpy of sublimation, but

\Delta_{\text{sub}}H = \Delta_{\text{fus}}H + \Delta_{\text{vap}}H = 6.01 + 40.68 = 46.69 \text{ kJ}\cdot\text{mol}^{-1}

The equation for the process is then

Mᵣ:                         18.02

         46.69 kJ + H₂O(s) ⟶ H₂O(g)

m/g:                       150

(a) Moles of water

\text{Moles} = \text{150 g} \times \dfrac{\text{1 mol}}{\text{18.02 g}} = \text{8.324 mol}

(b) Heat removed

46.69 kJ will remove 1 mol of ice.

\text{Heat removed} = \text{8.234 mol} \times \dfrac{\text{46.69 kJ}}{\text{1 mol}} = \textbf{389 kJ}\\\text{It takes $\large \boxed{\textbf{389 kJ}}$ to remove 150 g of ice}

2. Mass of water vapour in the freezer

For this calculation, we can use the Ideal Gas Law — pV = nRT

(a) Moles of water

Data:

p = 1.00 \times 10^{-3}\text{ torr } \times \dfrac{\text{1 atm}}{\text{760 torr}} = 1.316 \times 10^{-6}\text{ atm}

V = 5 L

T = (-80 + 273.15) K = 193.15 K

Calculation:

\begin{array}{rcl}pV & = & nRT\\1.316 \times 10^{-6}\text{ atm} \times \text{5 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{193.15 K }\\6.6 \times 10^{-6} & = & 15.85n\text{ mol}^{-1} \\n & = & \dfrac{6.6 \times 10^{-6}}{15.85\text{ mol}^{-1}}\\\\& = & 4.2 \times 10^{-7} \text{ mol}\\\end{array}

(b) Mass of water

\text{Mass} = 4.2 \times 10^{-7} \text{ mol} \times \dfrac{\text{18.02 g}}{\text{1 mol}} = 7.5 \times 10^{-6}\text{ g} = 7.5 \, \mu \text{g}\\\\\text{At any given time, there are $\large \boxed{\textbf{7.5 $\mu$g}}$ of water vapour in the freezer.}

3. Time for removal

You must remove 150 mL of water.

It takes 1 h to remove 1 mL of water.

\text{Time} = \text{150 mL} \times \dfrac{\text{1 h}}{\text{1 mL}} = \text{150 h} = \text{6.25 days}

5 0
4 years ago
It took many of the metals several minutes to begin to react. Once the reaction was initiated, several of these metals continued
notsponge [240]

Answer:

Passivation of Oxide layers of the metals.

Explanation:

Passivation is a non-electrolytic finishing process that makes most metals rust-resistant. The prosses removes free iron from the surface by using either nitric or citric acid. When this happens, it results to an inert, protective oxide layer that is very slow or less likely to chemically react with air and cause corrosion.

Passivity caused many of the metals several minutes to begin to react. Once the finishing process that makes metals less likely to react was eroded, reaction was initiated vigorously.

8 0
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expeople1 [14]
I think that the answer might be D beacuse if he body lacks calcuim thier DIET is low on calcium
7 0
4 years ago
Which of the following are likely to form an ionic bond? carbon and hydrogen carbon and sulfur magnesium and sulfur nitrogen and
Ann [662]
<span>magnesium and sulfur
(Magnesium is in family two which tends to form ionic bonds)(Elements in families 1 and 2 are very active metals that tend to form ionic bonds)</span>
5 0
4 years ago
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