Question

Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​

Answer 1

Avogadro's law states that in a mole of any substance, there are $6.022 \times 10^{23}$ atoms. This means that in the given sample, there are

$\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}$

• The atomic mass of sulfur is 32.06 amu.
• The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is

$32.06+2(15.9994=64.0588 \text{ g/mol}$

Therefore, the mass is:

$(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}$