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gayaneshka [121]
2 years ago
8

Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​

Chemistry
1 answer:
Misha Larkins [42]2 years ago
7 0

Avogadro's law states that in a mole of any substance, there are 6.022 \times 10^{23} atoms. This means that in the given sample, there are

\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}

  • The atomic mass of sulfur is 32.06 amu.
  • The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is

32.06+2(15.9994=64.0588 \text{ g/mol}

Therefore, the mass is:

(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}

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Sabendo que os calores de combustão do enxofre monoclínico e do enxofre rômbico são, respectivamente, - 297,2 kJ/mol e - 296,8 k
liq [111]

Responda:

+ 0,9kJ / mol

Explicação:

Dados os calores de combustão do enxofre monoclínico e enxofre rômbico como - 297,2 kJ / mol e - 296,8 kJ / mol, respectivamente para a variação na transformação de 1 mol de enxofre rômbico em enxofre monoclínico conforme mostrado pela equação;

S (mon.) + O2 (g) -> SO2 (g)

Uma vez que são todos 1 mol cada, a mudança na entalpia será expressa como ∆H = ∆H2-∆H1

Dado ∆H2 = -296,8kJ / mol

∆H1 = -297,2kJ / mol

∆H = -296,8 - (- 297,2)

∆H = -296,8 + 297,2

∆H = 297,2-296,8

∆H = + 0,9kJ / mol

Portanto, a mudança na entalpia da equação é + 0,9kJ / mol

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Explanation:

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It is answer C
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