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2 years ago

Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.

1 answer:

7 0

Avogadro's law states that in a mole of any substance, there are $6.022 \times 10^{23}$ atoms. This means that in the given sample, there are

$\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}$

The atomic mass of sulfur is 32.06 amu.
The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is

$32.06+2(15.9994=64.0588 \text{ g/mol}$

Therefore, the mass is:

$(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}$

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A sample of sodium sulfite has a mass of 2.80 g.

Gnom [1K]

<u>Answer:</u>

<u>For a:</u> The number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

<u>For b:</u> The number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

<u>For c:</u> The mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

<u>Explanation:</u>

The chemical formula of sodium sulfite is $Na_2SO_3$ . It is formed by the combination of 2 sodium $(Na^+)$ ions and 1 sulfite $(SO_3^{2-})$ ions

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sodium sulfite = 2.80 g

Molar mass of sodium sulfite = 126 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium sulfite}=\frac{2.80g}{126g/mol}=0.022mol$

<u>For a:</u>

Moles of sodium ions in sodium sulfite = (2 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(2\times 0.022\times 6.022\times 10^{23})=2.65\times 10^{22}$ number of sodium ions

Hence, the number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

<u>For b:</u>

Moles of sulfite ions in sodium sulfite = (1 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(1\times 0.022\times 6.022\times 10^{23})=1.325\times 10^{22}$ number of sulfite ions

Hence, the number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

<u>For c:</u>

Molar mass of sodium sulfite = 126 g/mol

According to mole concept:

$6.022\times 10^{23}$ number of formula units are present in 1 mole of a compound

Or, $6.022\times 10^{23}$ number of formula units of sodium sulfite have a mass of 126 grams

So, 1 formula unit of sodium sulfite will have a mass of = $\frac{126}{6.022\times 10^{23}}\times 1=2.09\times 10^{-22}g$

Hence, the mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

7 0

3 years ago

What happens when a solid is dissolved in a liquid

slava [35]

the solid particles take up the intermolecular spaces in the liquid.

8 0

3 years ago

PLEASE HELP THANKS:))))))

weeeeeb [17]

Explanation:

-plants that can absorb copper ions are grown on soil with low grade copper ores.

-the plants are burned and the copper compounds are within the Ash.

-copper ions can be leached from the Ash by adding sulphuric acid, this makes a solution of copper sulphate

-the displacement of scrap iron makes pure copper metals.

3 0

3 years ago

How many moles are in 5.6x1025 molecules of calcium oxide?

Vlad1618 [11]

Answer:

<h2>93.02 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...$

We have the final answer as

<h3>93.02 moles</h3>

Hope this helps you

8 0

2 years ago

Magnesium reacts with carbon dioxide to form magnesium oxide and pure solid carbon.

guajiro [1.7K]

Answer:

2Mg + 2CO₂ → 2MgO + C

Option a.

Explanation:

The chemical reactions are balanced in order to verify compliance with the Law of conservation of mass. This law states that in any chemical reaction, the mass of the reagents must be equal to the mass of the products

7 0

3 years ago

Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​

Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.