$21.45 x 6 = $128.7
$128.7 + $10.60 = $139.3
Charlie will have saved $139.3 in 7 months
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
Angie buys 1 software package and 3 months of game play
Kenny buys 1 software package and 4 months of game play
price of each software package = $20
total cost = $117
cost of one month game play = ?
let y is the cost of one month play
Angie buys 3 months game play and paid $20 = 20 + 3y
Kenny buys 4 months game play and paid $20 = 20 + 4y
total cost of both is $117
So the equation becomes,
(20 + 3y) + (20 + 4y) = 117
7y + 40 = 117
7y = 117 - 40
7y = 77
dividing with 7 on both sides, we get
y = 11
so, $11 is the cost of one month game play
Answer:
i can not see it
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
(-3 + 3) + (-2 + 3) =
= 0 + 1
= 1
