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3 years ago

The table represents the function f(x). If g(x) = -(x + 1)^2 - 10, which statement is true?

Mathematics

1 answer:

miskamm [114]3 years ago

5 0

Answer:

Answer C is correct.

Step-by-step explanation:

f(x) clearly has a maximum: y = +10 at x = 0.

Analyzing g(x) = -(x + 1)^2 - 10, we see that the vertex is at (-1, -10), and that the graph opens down. Thus, -10 is the maximum value; it occurs at x = -1.

Answer A is false. Both functions have max values.

Answer B is false. One max is y = 10 and the other is y = -10.

Answer C is correct. The max value of f(x), which is 10, is greater than the max value of g(x), which is -10.

Answer D is false. See Answer B, above.

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3 years ago

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3 years ago

Please tell the LCM of the following -

Arada [10]

Answer:

Below.

Step-by-step explanation:

I won't do all of these for you but I'll show you the general method.

First write each number as prime factors.

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The LCM is the multiple of all these factors EXCEPT if there is a duplicate number you only use it once.

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3 years ago

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I need to know how to do the answer and why that’s the anwer

Pavel [41]

Ok so the answer is
$4 {x}^{2}$

so we multiply numbers that have the same variable

$2 {x}^{3} \: \: \times {2x}^{ - 1} \\ \\$
multiply 2 x 2

$2 \times 2 = 4$
then multiply the exponents

$x ^{3} \times x ^{ - 1}$
multipling like this will look like addition.
${x}^{3} \times {x}^{ - 1} = {x}^{2}$
so in other words you could do it like this too
${x}^{3} + {x}^{ - 1} = {x}^{2}$
now add the exponent with 4
$4 + {x}^{2} = 4x ^{2}$

now for the last part
${y}^{3} + {y}^{ - 3} = 0$
because -3 and 3 added together make 0
$0 + 4 {x}^{2} = 4 {x}^{2}$
I hope this help(it looks complicated but it's very easy and I hope I helped you out)

6 0

3 years ago