Answer: 0.27648
Step-by-step explanation:
Given : The proportion of all individuals have group A blood : p=0.040
Total individuals give blood : n= 6
Let X be the number of individuals have group A blood.
Since all individual are independent of each other.

Formula :
, where n= sample size , p = probability of getting success in each trial.
The probability that exactly three of the individuals have group A blood. :

The probability that exactly three of the individuals have group A blood. is 0.27648
V=4/3π r^3
(3/4)V=π r^3
3V/4π = r^3
third root√(3V/4π)
<span><span>Hope this helps!
</span>and May the Force Be With You
</span><span>
-Jabba</span>
Answer:
there were 17 players left on the pitch
Step-by-step explanation:
17x24=408
648-408=240
If you use substitution the should be answer 30